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3 years ago

What Is the energy of a photon with a wavelength of 21nm? I

Chemistry

1 answer:

Sergio039 [100]3 years ago

8 0

Answer:

The energy of a photon with a wavelength of 350 nm is 5.7×10−19 J.

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How can we identify that the absorption of heat has occurred?

loris [4]

Answer:

rise in temperature and the effect it has on our global weather patterns

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3 years ago

Why is gold found in the pure state in nature?

Shkiper50 [21]

A native metal is any metal that is found in its metallic form, either pure or as an alloy, in nature. ... Over geological time scales, very few metals can resist natural weathering processes ! hope i helped!

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3 years ago

What is the Electronegativity difference of C and S?

umka21 [38]

Answer:

S 2.6 [2.58] & C is 2.6 [2.55]

Explanation:

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2 years ago

Calculate the [H+] and pH of a 0.0040 M hydrazoic acid solution. Keep in mind that the Ka of hydrazoic acid is 2.20×10−5. Use th

Vera_Pavlovna [14]

Answer:

$[H^+]=0.000285$

$pH=3.55$

Explanation:

In this, we can with the ionization equation for the hydrazoic acid ( $HN_3$ ). So:

$HN_3~~H^+~+~N_3^-$

Now, due to the Ka constant value, we have to use the whole equilibrium because this is not a strong acid. So, we have to write the Ka expression:

$Ka=\frac{[H^+][N_3^-]}{[HN_3]}$

For each mol of $H^+$ produced we will have 1 mol of $N_3^-$ . So, we can use "X" for the unknown values and replace in the Ka equation:

$Ka=\frac{X*X}{[HN_3]}$

Additionally, we have to keep in mind that $HN_3$ is a reagent, this means that we will be consumed. We dont know how much acid would be consumed but we can express a subtraction from the initial value, so:

$Ka=\frac{X*X}{0.004-X}$

Finally, we can put the ka value and solve for "X":

$2.2X10^-^5=\frac{X*X}{0.004-X}$

$2.2X10^-^5=\frac{X^2}{0.004-X}$

$X= 0.000285$

So, we have a concentration of 0.000285 for $H^+$ . With this in mind, we can calculate the pH value:

$pH=-Log[H^+]=-Log[0.000285]=3.55$

I hope it helps!

8 0

3 years ago

How is the billiards video an example of Newton’s third law? Prepare a statement using the following terms: action force, reacti

LuckyWell [14K]

Answer:

These two forces are called action and reaction forces and are the subject of Newton's third law of motion. Formally stated, Newton's third law is: For every action, there is an equal and opposite reaction. The statement means that in every interaction, there is a pair of forces acting on the two interacting objects.

Explanation:

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3 years ago

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