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mel-nik [20]
3 years ago
10

Giving brainlist for the right answers

Chemistry
1 answer:
Lady bird [3.3K]3 years ago
8 0

Answer:

10000000000

Explanation:

1 + 1 = 2 and if you divide 2 by 2 the answer is 1 and 1 x 100 = 100

and if you add 8 zeros to 100 the answer is 10000000000

#KeepOnLearning

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Identify the parts of the energy diagrams.
Lapatulllka [165]
  1. Answer:

Energy release is exothermic reaction whiles energy absorb is endothermic reaction

Explanation:

Exothermic reaction is when the reactant is above the product while endothermic the product is below the reactant in the diagrams we have some part as activation energy

4 0
4 years ago
Give the location of the elements found in the periodic table which have the same number of shells.
zmey [24]
B. All members within any group
3 0
3 years ago
Read 2 more answers
How many liters of oxygen gas, at standard
Karo-lina-s [1.5K]

Answer:

Explanation:

  • For the balanced reaction:

<em>4Fe(s) + 3O₂(g) → 2Fe₂O₃(s)​.</em>

It is clear that 4 mol of Fe react with 3 mol of O₂ to produce 2 mol of Fe₂O₃.

  • Firstly, we need to calculate the no. of moles of 35.8 grams of Fe metal:

no. of moles of Fe = mass/molar mass = (35.8 g)/(55.845 g/mol) = 0.64 mol.

  • Now, we can find the no. of moles of O₂ is needed to react with the proposed amount of Fe:

<em><u>Using cross multiplication:</u></em>

4 mol of Fe is needed to react with → 3 mol of O₂, from stichiometry.

0.64 mol of Fe is needed to react with → ??? mol of O₂.

∴ The no. of moles of O₂ needed = (3 mol)(0.64 mol)/(4 mol) = 0.48 mol.

  • Finally, we can get the volume of oxygen using the information:

<em>It is known that 1 mole of any gas occupies 22.4 L at standard P and T (STP).</em>

<em></em>

<em><u>Using cross multiplication:</u></em>

1 mol of O₂ occupies → 22.4 L, at STP conditions.

0.48 mol of O₂ occupies → ??? L.

∴ The no. of liters of O₂ = (0.48 mol)(22.4 L)/(1 mol) = 10.752 L.

5 0
4 years ago
What atomic nucleus has the fewest protons
maksim [4K]
Hydrogen-

Hydrogen is the answer because the number of protons is the atomic number.  All the elements have different atomic numbers and hydrogen has the least with an atomic number of 1.
3 0
4 years ago
The half-life of radon-222 is 3.82 days. If a sample of gas contains 4.38 μg of radon-222, how much will remain in the ample aft
LekaFEV [45]

Answer:

0.28 \mu g

Explanation:

We can write the amount of mass of radon-222 left after a time t by using the equation:

m(t) = m_0 (\frac{1}{2})^{t/t_{1/2}}

where

m_0 = 4.38 \mu g is the initial mass

t is the time

t_{1/2} = 3.82 d is the half-life

Substituting t = 15.2 d in the formula, we find

m(15.2 d) = (4.38 \mu g) (\frac{1}{2})^{15.2d/3.82 d}=0.28 \mu g

3 0
4 years ago
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