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kow [346]
3 years ago
14

Which of the binomials below is a factor of this trinomial? 3x2 + 18x - 21

Mathematics
2 answers:
Eddi Din [679]3 years ago
7 0
The answer is going to be: 3 • (x + 1) • (x - 7)
lutik1710 [3]3 years ago
3 0
I hope this helps you



3 (x^2+6x-7)


3 (x+7)(x-1)


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Sketch a graph of an elevator starting on the -2 floor and traveling at +5 floors per second. Label and scale the axes.
masya89 [10]
Make the x axis seconds and y axis floors. Your first point would be at (0,-2), then (1,3), then (2,8) and so on.

You could scale the axes just going by one
3 0
3 years ago
What is the solution of the system? Use elimination.
denis-greek [22]
Eliminate y's
multiply second equaiton by 4
4x+4y=-4

add to first equation

3x-4y=-24
<u>4x+4y=-4 +</u>
7x+0y=-28

7x=-28
divide both sides by 7
x=-4
sub back

x+y=-1
-4+y=-1
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(x,y)
(-4,3)
D is answer
4 0
3 years ago
Read 2 more answers
Taylor needs to put 8 hats in each box.
Stella [2.4K]

Hi,

64 ÷ 8 = x

X= the number of boxes

Hope I could help~ have a good day/night :]

5 0
2 years ago
Multiply out -6(2x-8)
Aleksandr-060686 [28]
It would be :
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6 0
3 years ago
Is square root 1 minus sine squared theta = cos Θ true? If so, in which quadrants does angle Θ terminate?
Cloud [144]

Answer:

True; quadrants I & IV

Step-by-step explanation:

We know the relation between sine and cosine function which is given by

\sin^2 \theta +\cos^2 \theta = 1

Let us solve this equation for cosine function.

\cos^2 \theta = 1-\sin^2 \theta

Take square root both sides. When ever we take square root we need to write the solution in plus minus form

\sqrt{\cos^2 \theta}=\pm\sqrt{1-\sin^2 \theta}

\cos \theta=\pm\sqrt{1-\sin^2 \theta}

\cos \theta=-\sqrt{1-\sin^2 \theta}, \sqrt{1-\sin^2 \theta}

If Θ is in quadrants I and IV then the value will be positive and if Θ is in II and III quadrant then the value is negative.

Hence, if Θ is in quadrants I & IV, then we have

\cos \theta=\sqrt{1-\sin^2 \theta}

Thus, the correct option is: True; quadrants I & IV


6 0
3 years ago
Read 2 more answers
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