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VLD [36.1K]
3 years ago
7

Write an equation of the line that passes through the given point and is parallel

Mathematics
1 answer:
Semenov [28]3 years ago
3 0

So when an equation or set of equations are parallel, that means that the equations have the same slope.

for the given equation, it has a slope of 2.

so to find the equation of the other line, you substitute the coordinate and slope into the equation y=mx+b.

-2=2(3)+b

-2=6+b

-8=b

So your function that is parallel has a slope of 2 and a y intercept at -8 or (0,-8).

Then just substitute those values into the equation.

y=2x-8

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. He rowed 3 1/2 miles in 1/2 hour.What is the average speed in miles per hour.
Rudiy27

Answer:

7 miles per hour

Step-by-step explanation:

3 1/2 miles = 7/2 miles

1/2 hours= 30 minutes

So,

In 30 mins, travelled 7/2 miles

In 1 min, travelled 7/2 ÷ 30= 7/2× 1/30 = (7×1)/(2×30) = 7/60 miles

In 60 mins, travelled (7×60)/60 miles = 420/60 miles = 7 miles.

Hence, the speed is 7 miles per hour.

Hope this helps :)

7 0
2 years ago
5r-2=6r+5 what does r equal​
Anuta_ua [19.1K]

Answer:

r=-7

Step-by-step explanation:

8 0
3 years ago
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Write an equation to represent the relationship found in the table
PilotLPTM [1.2K]

Answer:

15= 5x+ 2

Step-by-step explanation:

y= mx+b

y is the intercept,

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2 years ago
Find the dimensions of an open rectangular box with a square base that holds 2000 cubic cm and is constructed with the least bui
Vesnalui [34]
<h3>The dimensions of the given rectangular box are:</h3><h3>L  =   15.874 cm  , B  =  15.874 cm   , H = 7.8937 cm</h3>

Step-by-step explanation:

Let us assume that the dimension of the square base = S x S

Let us assume the height of the rectangular base = H

So, the total area of the open rectangular box  

= Area of the base +  4 x ( Area of the adjacent faces)

=  S x S  +  4 ( S x H)   = S² +  4 SH   ..... (1)

Also, Area of the box  = S x S x H  =  S²H

⇒ S²H = 2000

\implies H = \frac{2000}{S^2}

Substituting the value of H in (1), we get:

A = S^2 + 4 SH =  S^2 + 4 S(\frac{2000}{S^2}) =  S^2 + (\frac{8000}{S})\\\implies A  =  S^2 + (\frac{8000}{S})

Now, to minimize the area put :

(\frac{dA}{dS} ) = 0 \implies 2S  - \frac{8000}{S^2}  = 0\\\implies S^3 = 4000\\\implies S  = 15.874 \approx 16 cm

Putting the value of S  = 15.874 cm in the value of H , we get:

\implies H = \frac{2000}{S^2}  =  \frac{2000}{(15.874)^2} = 7.8937 cm

Hence, the dimensions of the given rectangular box are:

L  =   15.874 cm

B  = 15.874 cm

H = 7.8937 cm

3 0
3 years ago
How to determine a midpoint for a frequency table?
Semmy [17]
The class midpoint is the lower class limit plus the upper class limit divided by 2 . Add the midpoints column to the original table.
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3 years ago
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