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Ksivusya [100]
3 years ago
5

Does anybody love me

Mathematics
2 answers:
IrinaVladis [17]3 years ago
5 0

Answer:

Yes

Step-by-step explanation:

You like you're self

Oksana_A [137]3 years ago
3 0

Answer:

~Hey~ how r u?? Lol Thqnks for the free points +

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What would 2/8 be as a decimal?
lukranit [14]
Think about it 2/8 = 1/4 1/4 = .25
7 0
3 years ago
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Which conversion factor below you can use to convert gallons to pints?
Korvikt [17]

Answer: 1 Cup = 8 fl oz

Step-by-step explanation:

7 0
3 years ago
find the dimensions of a rectangle whose width is 4 miles less than its length and whose area is 96 square miles
Scilla [17]

Answer:

12 miles by 8 miles

Step-by-step explanation:

Let length be represented by x

Since width is 4 miles less than the length, therefore, the width will be (x-4) miles

Area=Length*Width

Area=x(x-4)=x^{2}-4x

Area is given hence

x^{2}-4x=96

To write the above equation as a quadratic equation

x^{2}-4x-96=0

By factorization, we find two numbers whose sum is -4 and product is -96, these are 8 and -12. Therefore, taking these two numbers back to our equation

(x+8)(x-12)=0

Therefore, x=-8 or 12

Equally, using quadratic formula of

x=\frac{-b±\sqrt{b^{2} -4ac}}{2a} for equation ax^{2}+bx+c=0 and in our case a=1, b=-4 and c=-96

x=\frac{4±\sqrt{(-4)^{2} -(4*1*-96)}}{2*1}

x=-8 or 12

Since length can't be negative, hence x=12

The length is 12 miles

Width=12-4=8 miles

Dimensions: 12 miles by 8 miles

3 0
3 years ago
The domain of the function is given. Find the range.
Afina-wow [57]
The range is how much it spans in f(x), f(x) is a line, it has no max/min, so it's enough to substitute the least and greatest values of your domain:

f(-2) = -5, f(4)=7,

Range = [-5,7]
8 0
4 years ago
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Show that cos2x=cosx
PSYCHO15rus [73]

cos (2x) = cos x

2 cos^2 x -1 = cos x   using the double angle formula

2 cos ^2 x -cos x -1 =0

factor

(2 cos x+1) ( cos x -1) = 0

using the zero product property

2 cos x+1 =0    cos x -1 =0

2 cos x = -1       cos x =1

cos x = -1/2       cos x=1

taking the arccos of each side

arccos cos x = arccos (-1/2)         arccos cos x = arccos 1

x = 120 degrees   x=-120   degrees           x=0

remember you get 2 values ( 2nd and 3rd quadrant)

these are the principal values

now we need to add 360

x = 120+ 360n      x=-120+ 360n      x = 0 + 360n  where n is an integer


3 0
4 years ago
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