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3 years ago

Does anybody love me

Mathematics

2 answers:

IrinaVladis [17]3 years ago

5 0

Answer:

Yes

Step-by-step explanation:

You like you're self

Oksana_A [137]3 years ago

3 0

Answer:

~Hey~ how r u?? Lol Thqnks for the free points +

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The graph of a linear equation contains the points (3,11) and (-2,11). Which point also lies on the graph?(YOU MUST SHOW WORK)

dexar [7]

Y= ax+b

when x=3, y=11 and when x= -2, y=11
3a+b=11
-2a+b=11 | * -1
3a+b=11
2a-b=-11
------------
5a=0, a=0:5, a=0
⇒ b=11
y=11 for every x
So ( 1,11) or (2,11) are also points on the graph

3 0

2 years ago

Jordan has 9 dimes and some quarters in her pocket. The value of her coins is $3.65. Which equation

Ratling [72]

Answer:

scientific notation would work better

8 0

3 years ago

Read 2 more answers

Find an equation of the circle that satisfies the given conditions.

hodyreva [135]

The equation of a circle:
$(x-h)^2+(y-k)^2=r^2$
(h,k) - the coordinates of the centre
r - the radius

The midpoint of the diameter is the centre of a circle.
The coordinates of the midpoint:
$(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$
(x₁,y₁), (x₂,y₂) - the coordinates of endpoints

$P(-1,1) \\
x_1=-1 \\ y_1=1 \\ \\ Q(5,9) \\ x_2=5 \\ y_2=9 \\ \\
\frac{x_1+x_2}{2}=\frac{-1+5}{2}=\frac{4}{2}=2 \\ \frac{y_1+y_2}{2}=\frac{1+9}{2}=\frac{10}{2}=5$

The centre of the circle is (2,5).

The radius is the distance between an endpoint of the diameter and the centre.
The formula for distance:
$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$(-1,1) \\ x_1=-1 \\ y_1=1 \\ \\ (2,5) \\ x_2=2 \\ y_2=5 \\ \\ d=\sqrt{(2-(-1))^2+(5-1)^2}=\sqrt{3^2+4^2}=\sqrt{9+16}=\sqrt{25}=5$

The radius is 5.

$(x-2)^2+(y-5)^2=5^2 \\
\boxed{(x-2)^2+(y-5)^2=25}$

4 0

2 years ago

Pls answer asap, show work pls :(

coldgirl [10]

Answer:

2.Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form: ( 3 , 5 )

Equation Form: x = 3 , y = 5

3.Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form: ( 2 , 8 )

4.Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form: ( 2 , − 3 )

Step-by-step explanation:

6 0

3 years ago

Please Help me Please Please the question and options are in the picture

Lapatulllka [165]

If you eliminate the parentheses, then add mq, you have

... y - p + mq = mx

Then dividing by m gives you the equation for x:

... x = (y - p + mq)/m

3 0

2 years ago