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1 year ago

ANSWER AND EXPLAIN PLEASE ILL MARK BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

rusak2 [61]1 year ago

4 0

Answer:

hiii 7272<>*~_+89×[0<×<×*×

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ANSWER PLEASE I WILL MARK AS BRAINLIEST

ICE Princess25 [194]

Answer:

162 mL

Step-by-step explanation:

1.Convert all volumes to millilitres

(a) Chlorpheniramine

V = 100 mL

(b) Lidocaine

$V = \text{2 fl oz} \times \dfrac{\text{29.57 mL}}{\text{1 fl oz}} = \textbf{59 mL}$

(c) Banana flavouring

$V = \dfrac{1}{2}\text{ tsp} \times \dfrac{\text{4.928 mL}}{\text{1 tsp}} = \textbf{2.5 mL}$

2.Calculate the total volume

Chlorpheniramine = 100 mL

Lidocaine = 59

Banana flavouring = <u> 2.5 </u>

TOTAL = 162 mL

3 0

2 years ago

Solve the algebraic equation: 2x + 4 = -16

lora16 [44]

Answer:

-10

Step-by-step explanation:

subtract 4 from both sides

divide by 2

5 0

2 years ago

Read 2 more answers

What is -4 (-6x + 3) = 12

IgorC [24]

Answer: x = 1

Step-by-step explanation:

Simplifying

-4(-6x + 3) = 12

Reorder the terms:

-4(3 + -6x) = 12

(3 * -4 + -6x * -4) = 12

(-12 + 24x) = 12

Solving

-12 + 24x = 12

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '12' to each side of the equation.

-12 + 12 + 24x = 12 + 12

Combine like terms: -12 + 12 = 0

0 + 24x = 12 + 12

24x = 12 + 12

Combine like terms: 12 + 12 = 24

24x = 24

Divide each side by '24'.

x = 1

Simplifying

x = 1

6 0

2 years ago

Read 2 more answers

When is the constant of proportionality the same as the unit rate when comparing two quantities?

Stels [109]

Answer: C

Step-by-step explanation: They are never the same

4 0

2 years ago

Hi guys, can anyone help me with this triple integral? Many thanks:)

Crank

Another triple integral. We're integrating over the interior of the sphere

$x^2+y^2+z^2=2^2$

Let's do the outer integral over z. z stays within the sphere so it goes from -2 to 2.

For the middle integral we have

$y^2=4-x^2-z^2$

x is the inner integral so at this point we conservatively say its zero. That means y goes from $-\sqrt{4-z^2}$ and $+\sqrt{4-z^2}$

Similarly the inner integral x goes between $\pm-\sqrt{4-y^2-z^2}$

So we rewrite the integral

$\displaystyle \int_{-2}^{2} \int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}} \int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dx \; dy \; dz$

Let's work on the inner one,

$\displaystyle\int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dz$

There's no z in the integrand, so we treat it as a constant.

$=(x^2+xy+y^2)z \bigg|_{z=-\sqrt{4-y^2-z^2}}^{z=\sqrt{4-y^2-z^2}}$

So the middle integral is

$\displaystyle\int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}}2(x^2+xy+y^2)\sqrt{4-y^2-z^2} \ dy$

I gotta go so I'll stop here, sorry.

7 0

2 years ago

Read 2 more answers