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arlik [135]
3 years ago
7

Plz solve the 7th question immediately ....Help me......

Mathematics
1 answer:
Lynna [10]3 years ago
3 0

Answer:

The value of x is 8cm. The length of 3 sides are 8cm, 15cm and 17cm.

Step-by-step explanation:

Using Pythagoras' Theorem, a²+b² = c² :

Let a be x cm,

Let b be x+7 cm,

Let c be 2x+1 cm

x² + (x+7)² = (2x+1)²

x² + x² + 14x + 49 = 4x² + 4x + 1

2x² + 14x + 49 = 4x² + 4x + 1

Then, move all the variables to one side and solve it to find the value of x :

4x² + 4x + 1 - 2x² - 14x - 49 = 0

2x² - 10x - 48 = 0

2(x² - 5x - 24) = 0

x² - 5x - 24 = 0

(x-8)(x+3) = 0

x - 8 = 0

x = 8 cm

x + 3 = 0

x = -3 cm (rejected)

Substitute the x value into the length of a,b and c :

a = x

= 8 cm

b = x + 7

= 8 + 7

= 15 cm

c = 2x + 1

= 2(8) + 1

= 16 + 1

= 17 cm

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<h3>Answer:  9</h3>

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Work Shown:

a = unknown  = leg #1

b = 12  = leg #2

c = 15 = hypotenuse

Plug those values into the pythagorean theorem and solve for 'a'

a^2 + b^2 = c^2

a^2 + (12)^2 = (15)^2  .... substitution

a^2 + 144 = 225

a^2 = 225 - 144  ... subtracting 144 from both sides

a^2 = 81

a = sqrt(81)  .... applying square root to both sides

a = 9

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3 years ago
Multiply. Express each answer as a decimal.<br><br> 12⋅15<br> 34⋅200<br> (0.2)⋅60<br> (0.75)⋅20
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Answer:

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Which value is furthest from 0 on the number line?<br> a. 30<br> b. -31<br> c. 30.5<br> d. -31.5
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Answer:

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Step-by-step explanation:


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20 POINTS!!! Use the quadratic formula above to solve for h(t) = -4.9t^2 + 8t + 1 where h is the height of the ball in meters an
Elina [12.6K]

Answer:

Two solutions: -0.12 and 1.75.

Step-by-step explanation:

The quadratic formula is:

\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}. Assuming that the x² term is a, the x term is b, and the constant is c, we can plug the values into the equation.

\begin{array}{*{20}c}{\frac{{ - 8 \pm \sqrt {8^2 - 4\cdot-4.9\cdot1} }}{{2\cdot-4.9}}} \end{array}

\begin{array}{*{20}c}{\frac{{ - 8 \pm \sqrt {64 + 19.6} }}{{-9.8}}} \end{array}

\begin{array}{*{20}c}{\frac{{ - 8 \pm \sqrt {83.6} }}{{-9.8}}} \end{array}

\begin{array}{*{20}c}{\frac{{ - 8 \pm \sqrt {9.14} }}{{-9.8}}} \end{array}

\frac{-8 + 9.14}{-9.8} = -0.12

\frac{-8-9.14}{-9.8} =1.75

Hope this helped!

3 0
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