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arlik [135]
3 years ago
7

Plz solve the 7th question immediately ....Help me......

Mathematics
1 answer:
Lynna [10]3 years ago
3 0

Answer:

The value of x is 8cm. The length of 3 sides are 8cm, 15cm and 17cm.

Step-by-step explanation:

Using Pythagoras' Theorem, a²+b² = c² :

Let a be x cm,

Let b be x+7 cm,

Let c be 2x+1 cm

x² + (x+7)² = (2x+1)²

x² + x² + 14x + 49 = 4x² + 4x + 1

2x² + 14x + 49 = 4x² + 4x + 1

Then, move all the variables to one side and solve it to find the value of x :

4x² + 4x + 1 - 2x² - 14x - 49 = 0

2x² - 10x - 48 = 0

2(x² - 5x - 24) = 0

x² - 5x - 24 = 0

(x-8)(x+3) = 0

x - 8 = 0

x = 8 cm

x + 3 = 0

x = -3 cm (rejected)

Substitute the x value into the length of a,b and c :

a = x

= 8 cm

b = x + 7

= 8 + 7

= 15 cm

c = 2x + 1

= 2(8) + 1

= 16 + 1

= 17 cm

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Answer:


In the given figure the sides of triangle measures as follows:


AB= 4 units,


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Since triangle ABC is right angled triangle, to find AC we will have to use Pythagorean theorem,


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Plugging the values of AB and BC to find AC,


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Now if the triangle is dilated by a scale factor of 2, each side will be multiplied by 2 to get the new triangle A'B'C'


side A'B' = 2* AB = 2*4= 8 units


side B'C' = 2* BC = 2*6 =12 units


side A'C' = 2*AC = 2*7.48 = 14.96 units


Perimeter of triangle = sum of three sides


Perimeter of triangle A'B'C' = A'B' + B'C' + A'C'= 8+12 + 14.96 = 34.96 units.


Perimeter of triangle ABC = AB+BC + AC = 4+6+7.48 = 17.48 units.


Perimeter of triangle A'B'C' = 2* Perimeter of triangle ABC


The perimeter of new triangle A'B'C' is 34.96 units which is twice that of triangle ABC.


Answer : A) The perimeter of A'B'C' is 2 times the perimeter of ABC.



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