<span><span>y = 2 + 2sec(2x)
The upper part of the range will be when the secant has the smallest
positive value up to infinity.
The smallest positive value of the secant is 1
So the minimum of the upper part of the range of
y = 2 + 2sec(2x) is 2 + 2(1) = 2 + 2 = 4
So the upper part of the range is [4, )
The lower part of the range will be from negative infinity
up to when the secant has the largest negative value.
The largest negative value of the secant is -1
So the maximum of the lower part of the range of
y = 2 + 2sec(2x) is 2 + 2(-1) = 2 - 2 = 0
So the lower part of the range is (, 0].
Therefore the range is (, 0] U [4, )
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Answer:
B is the correct answer!
Step-by-step explanation:
It starts at 6 and ends at 11.
Hope this helps & please mark brainiest....
Answer:
B. 66
Step-by-step explanation:
Substitute x = 3
Multiply in the parentheses
(6 + 192) Add
(198) Multiply
66
Answer:200cubic sand
Step-by-step explanation:
cubic means 3 times. And you lose 100 sand from wind 10 times.
