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Masja [62]
2 years ago
10

A six-sided die is rolled 150 times.

Mathematics
2 answers:
leva [86]2 years ago
7 0

Answer:

approximately 75 times

suter [353]2 years ago
5 0

Answer:

approximately 75 times

Step-by-step explanation:

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$51.2

Step-by-step explanation:

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The German Club is planning a ski trip. The club will pay $500 toward the trip, and each member going on the trip will pay $115.
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3 years ago
A large operator of timeshare complexes requires anyone interested in making a purchase to first visit the site of interest. His
morpeh [17]

Answer:

There is a 21.053% probability that this person made a day visit.

There is a 39.474% probability that this person made a one night visit.

There is a 39.474% probability that this person made a two night visit.

Step-by-step explanation:

We have these following percentages

20% select a day visit

50% select a one-night visit

30% select a two-night visit

40% of the day visitors make a purchase

30% of one night visitors make a purchase

50% of two night visitors make a purchase

The first step to solve this problem is finding the probability that a randomly selected visitor makes a purchase. So:

P = 0.2(0.4) + 0.5(0.3) + 0.3(0.5) = 0.38

There is a 38% probability that a randomly selected visitor makes a purchase.

Now, as for the questions, we can formulate them as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

Suppose a visitor is randomly selected and is found to have made a purchase.

How likely is it that this person made a day visit?

What is the probability that this person made a day visit, given that she made a purchase?

P(B) is the probability that the person made a day visit. So P(B) = 0.20

P(A/B) is the probability that the person who made a day visit made a purchase. So P(A/B) = 0.4

P(A) is the probability that the person made a purchase. So P(A) = 0.38

So

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.4*0.2}{0.38} = 0.21053

There is a 21.053% probability that this person made a day visit.

How likely is it that this person made a one-night visit?

What is the probability that this person made a one night visit, given that she made a purchase?

P(B) is the probability that the person made a one night visit. So P(B) = 0.50

P(A/B) is the probability that the person who made a one night visit made a purchase. So P(A/B) = 0.3

P(A) is the probability that the person made a purchase. So P(A) = 0.38

So

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.5*0.3}{0.38} = 0.39474

There is a 39.474% probability that this person made a one night visit.

How likely is it that this person made a two-night visit?

What is the probability that this person made a two night visit, given that she made a purchase?

P(B) is the probability that the person made a two night visit. So P(B) = 0.30

P(A/B) is the probability that the person who made a two night visit made a purchase. So P(A/B) = 0.5

P(A) is the probability that the person made a purchase. So P(A) = 0.38

So

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.3*0.5}{0.38} = 0.39474

There is a 39.474% probability that this person made a two night visit.

3 0
3 years ago
The manager of a school store orders 250 pencils at the beginning of the
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Answer:

152 pencils remain after 14 days of school.

Step-by-step explanation:

Replace x in this formula with 14 (14 days):

f(14) = 250 - 7(14) = 250 - 98 = 152

152 pencils remain after 14 days of school.

8 0
3 years ago
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