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2 years ago

what is c to the negative 3 power and d to the 5 power over f to the 3 power and g to the negative 7 power

Mathematics

1 answer:

julia-pushkina [17]2 years ago

8 0

Answer:

C^-3+d^5/f^3+g^-7

Step-by-step explanation:

The answer is as seen above

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I need help with multiplying and dividing powers

Tamiku [17]

You need to know these two formulas:

$\huge a^b \times a^c = a^{b+c}\\\\\huge \frac{a^b}{a^c}=a^{b-c}$

For example,

$5^2 \times 5^3 = 5^{2+3} = 5^5$

$\frac{2^6}{2^4} = 2^{6-4} = 2^2$

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2 years ago

What’s the radius of a circle with an area of 123 square feet

Katyanochek1 [597]

Answer:

6.25716517287

Step-by-step explanation:

Area of circle = π × r²

→ 123 = π × r²

⇒ Divide both sides by π

→ 39.1521160006 = r²

⇒ Square root both sides

→ 6.25716517287 = r

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3 years ago

Explain the difference between squaring a number and square roots.

Elena L [17]

Answer:

mews jh

Step-by-step explanation:

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3 years ago

How many sides does a cube have

Lostsunrise [7]

A cube has 6 sides on it. Just think of a dice.

Hope I Helped!!!

5 0

3 years ago

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Solve x2 – 7x = –13.

aleksklad [387]

we have

$x^{2} -7x=-13$

Complete the square. Remember to balance the equation by adding the same constants to each side

$x^{2} -7x+3.5^{2}=-13+3.5^{2}$

$x^{2} -7x+12.25=-13+12.25$

$x^{2} -7x+12.25=-0.75$

Rewrite as perfect squares

$(x-3.5)^{2}=-0.75$

remember that

$i=\sqrt{-1}$

Square root both sides

$(x-3.5)=(+/-)\sqrt{-0.75}$

$(x-3.5)=(+/-)\sqrt{-1*0.75}$

$(x-3.5)=(+/-)\sqrt{0.75}i$

$x1=3.5+\sqrt{0.75}i$

$x2=3.5-\sqrt{0.75}i$

Simplify

$\sqrt{0.75}=\frac{\sqrt{3}}{2}$

$x1=3.5+\frac{\sqrt{3}}{2}i$

$x2=3.5-\frac{\sqrt{3}}{2}i$

therefore

<u>the answer is</u>

$x1=3.5+\frac{\sqrt{3}}{2}i$

$x2=3.5-\frac{\sqrt{3}}{2}i$

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3 years ago

Read 2 more answers