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spin [16.1K]
3 years ago
9

The width of a rectangle measures (3.8b-1.5) centimeters, and it's length measures (4.3b-7.2) centimeters. Which expression repr

esents the perimeter, in centimeters, of the rectangle
A.) -17.4+16.2b
B.) -2.9+2.3b
C.) 4.6-5.8
D.) 8.1b-8.7
Mathematics
1 answer:
vivado [14]3 years ago
6 0

Answer:

-17.4+16.2b

Step-by-step explanation:

I just guessed and it was right

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Read 2 more answers
The function f(x,y) = xy has an absolute maximum value and absolute minimum value subject to the constraint 2x^2 + 3y^2 - 3xy =
marta [7]

Answer:

The absolute minimum of f(x,y) = 8.107

The absolute maximum of f(x,y) = 24.326

Step-by-step explanation:

f(x,y) = xy. The constraint equation is 2x² + 3y² - 3xy = 49

Let g(x,y) = 2x² + 3y² - 3xy - 49

df/dx = y and df/dy = x , dg/dx = 4x - 3y and dg/dy = 6y - 3x

Using Lagrange multipliers,

df/dx = λdg/dx and df/dy = λdg/dy

So,

y = λ(4x - 3y)   (1 )and x = λ(6y - 3x)  (2)

y = 4λx - 3λy

y + 3λy = 4λx

y(1 + 3λ) = 4λx

y = 4λx/(1 + 3λ)

Substituting y into (2), we have

x = λ(6y - 3x)

x = λ(6[4λx/(1 + 3λ)] - 3x)

x =  24λ²x/(1 + 3λ) - 3λx

24λ²x/(1 + 3λ) - 3λx - x = 0

[24λ²/(1 + 3λ) - 3λ - 1]x = 0

⇒ [24λ²/(1 + 3λ) - 3λ - 1] = 0 since x ≠ 0

[24λ²/(1 + 3λ) - 3λ - 1] = 0

⇒[24λ²/(1 + 3λ) - (3λ + 1)] = 0

[24λ² - (3λ + 1)²] = 0

24λ² - 9λ² - 6λ - 1 = 0

15λ² - 6λ - 1 = 0

Using the quadratic formula,

λ = = \frac{-(-6) +/- \sqrt{(-6)^{2} - 4 X 15 X (-1)} }{2 X 15}\\= \frac{6) +/- \sqrt{36 + 60)} }{30}\\= \frac{6 +/- \sqrt{96)} }{30}\\= \frac{6 +/- 4\sqrt{6)} }{30}\\

λ = (6 + 4√6)/30 or (6 - 4√6)/30

λ = (3 + 2√6)/15 = 0.527 or (3 - 2√6)/15 = -0.127

Substituting y into the constraint equation, we have

2x² + 3y² - 3xy = 49

2x² + 3(4λx/(1 + 3λ))² - 3x(4λx/(1 + 3λ)) = 49

2x² + 12λ²x²/(1 + 3λ))² - 12λx²/(1 + 3λ) = 49

[2 + 12λ²/(1 + 3λ)² - 12λ/(1 + 3λ)}x² = 49

[2(1 + 3λ)² + 12λ² - 12λ(1 + 3λ)]x²/(1 + 3λ)² = 49

[2(1 + 6λ + 9λ²) + 12λ² - 12λ + 36λ²)]x²/(1 + 3λ)² = 49

[2 + 12λ + 18λ² + 12λ² - 12λ + 36λ²)]x²/(1 + 3λ)² = 49

[2 + 6λ²]x²/(1 + 3λ)² = 49

x² = 49(1 + 3λ)²/(2 + 6λ²)

x² = 49(1 + 3λ)²/2(1 + 3λ²)

x = √[49(1 + 3λ)²/2(1 + 3λ²)]

x = ±7√[(1 + 3λ)²/2(1 + 3λ²)]

Substituting λ = (3 + 2√6)/15 = 0.527 or (3 - 2√6)/15 = -0.127

x = ±7√[(1 + 3(0.527))²/2(1 + 3(0.527)²)] or ±7√[(1 + 3(-0.127))²/2(1 + 3(-0.127)²)]

x = ±7√[(6.662/3.666] or ±7√[0.3831/1.9032)]

x = ±7√1.8172 or ±7√0.2012

x = ±9.436 or ±3.141

Substituting x and λ into y, we have

y = 4λx/(1 + 3λ)

y = 4(0.527)(±3.141)/(1 + 3(0.527)) or  4(-0.127)(±3.141)/(1 + 3(-0.127))

y = ±6.6621/2.581    or ±1.5956/0.619

y = ±2.581 or ±2.578

The minimum value of f(x,y) is gotten at the minimum values of x and y which are x = -3.141 and y = -2.581

So f(-3.141,-2.581) = -3.141 × -2.581 = 8.107

The maximum value of f(x,y) is gotten at the minimum values of x and y which are x = +9.436 and y = +2.578

So f(+9.436,+2.578) = +9.436 × +2.578 = 24.326

5 0
4 years ago
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