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2 years ago

8

The following are the ages (years) of 5 people in a room: 24 , 24 , 15 , 16 , 19 A person enters the room. The mean age of the 6

people is now 19. What is the age of the person who entered the room?

1 answer:

olga_2 [115]2 years ago

4 0

Answer:

16 years old.

Step-by-step explanation:

(24+24+15+16+19+X) / 6 = 19

(98 + X) / 6 = 19

98 + X = (19)*(6)

98 + X = 114

X = 114-98

X = 16

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The first step in solving 3.17 t - 2.431 = 5.06 is to divide both sides of the equation by 3.17. TrueFalse

Pavlova-9 [17]

Answer:

False

Step-by-step explanation:

$3.17t - 2.431 = 5.06 \\ 3.17t = 5.06 + 2.431 \\ 3.17t = 7.491 \\ \frac{3.17t}{3.17} = \frac{7.491}{3.17} \\ t = 2.363$

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3 years ago

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Answer the following questions.

SOVA2 [1]

Answer:

43

Step-by-step explanation:

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2 years ago

Find the location of Y, the midpoint of XZ X is located at (3,-9)

Levart [38]

The location of point Y is the point -3 on the number line

Here, we want to find the location of Y

let us say the point 0 represents the origin

The coordinates of point x will be (-9,0) while the coordinates of point z will be (3,0)

To find the location of Y , we proceed to use the midpoint formula as follows;

$(x,y)=\frac{x_{1\text{ }}+x_2}{2},\frac{y_{1\text{ }}+y_2}{2}$

Thus, we have;

(-9 + 3)/2 , (0 + 0)/2

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= (-3 , 0)

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10 months ago

Two different simple random samples are drawn from two different populations. The first sample consists of 30 people with 16 hav

Furkat [3]

Answer:

There is no significant evidence that p1 is different than p2 at 0.01 significance level.

99% confidence interval for p1-p2 is -0.171 ±0.237 that is (−0.408, 0.066)

Step-by-step explanation:

Let p1 be the proportion of the common attribute in population1

And p2 be the proportion of the same common attribute in population2

$H_{0}$ : p1-p2=0

$H_{a}$ : p1-p2≠0

Test statistic can be found using the equation:

$z=\frac{p2-p1}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}}$ where

p1 is the sample proportion of the common attribute in population1 ( $\frac{16}{30} =0.533$ )

p2 is the sample proportion of the common attribute in population2 ( $\frac{1337}{1900} =0.704$ )

p is the pool proportion of p1 and p2 ( $\frac{16+1337}{30+1900}=0.701$ )

n1 is the sample size of the people from population1 (30)

n2 is the sample size of the people from population2 (1900)

Then $z=\frac{0.704-0.533}{\sqrt{{0.701*0.299*(\frac{1}{30} +\frac{1}{1900}) }}}$ ≈ 2.03

p-value of the test statistic is 0.042>0.01, therefore we fail to reject the null hypothesis. There is no significant evidence that p1 is different than p2.

99% confidence interval estimate for p1-p2 can be calculated using the equation

p1-p2± $z*\sqrt{\frac{p1*(1-p1)}{n1}+\frac{p2*(1-p2)}{n2}}$ where

z is the z-statistic for the 99% confidence (2.58)

Thus 99% confidence interval is

0.533-0.704± $2.58*\sqrt{\frac{0.533*0.467}{30}+\frac{0.704*0.296}{1900}}$ ≈ -0.171 ±0.237 that is (−0.408, 0.066)

7 0

3 years ago

In 2011, the Institute of Medicine (IOM), a non-profit group affiliated with the Select one US National Academy of Sciences, rev

Sergio [31]

Answer:

B. Yes, there are at least 10 people with weak bones and 10 people with strong bones in each group.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$

The correct answer is:

B. Yes, there are at least 10 people with weak bones and 10 people with strong bones in each group.

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3 years ago