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Sliva [168]
2 years ago
10

A chess tournament was being held. This single-elimination tournament (in which paired competitors

Mathematics
1 answer:
Sergeeva-Olga [200]2 years ago
5 0

Answer:

A total of 15 matches were played.

Step-by-step explanation:

To determine the number of matches that were played in the chess tournament, knowing that there are 16 participants who face each other in a tournament of direct elimination, the following logical reasoning must be carried out:

In the first round there are 16 players, so being matches between 2 players, there are 8 matches (16/2). In the second round, applying the same reasoning and taking into account that there are only 8 players left, since the others have been eliminated, there are 4 matches (8/2). The same in the semifinals, where there are 2 games (4/2), and finally, the final to a single game.

Therefore, since 8 + 4 + 2 + 1 equals 15, the number of matches played in the tournament is 15.

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Hatshy [7]

Answer:

20.5 : 61.5

Step-by-step explanation:

1:3

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A small business assumes that the demand function for one of its new products can be modeled by p = Cekx. When p = $40, x = 1000
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Answer:

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Step-by-step explanation:

p=Ce^{kx}\\40=Ce^{k1000}\\30=Ce^{k1400}\\

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ln(40) = ln(C) + 1000k\\ln(30) = ln(C) + 1400k

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