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3 years ago

A chess tournament was being held. This single-elimination tournament (in which paired competitors

Mathematics

1 answer:

Sergeeva-Olga [200]3 years ago

5 0

Answer:

A total of 15 matches were played.

Step-by-step explanation:

To determine the number of matches that were played in the chess tournament, knowing that there are 16 participants who face each other in a tournament of direct elimination, the following logical reasoning must be carried out:

In the first round there are 16 players, so being matches between 2 players, there are 8 matches (16/2). In the second round, applying the same reasoning and taking into account that there are only 8 players left, since the others have been eliminated, there are 4 matches (8/2). The same in the semifinals, where there are 2 games (4/2), and finally, the final to a single game.

Therefore, since 8 + 4 + 2 + 1 equals 15, the number of matches played in the tournament is 15.

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Suppose that the function f is defined. , for all real numbers, as follows.

aivan3 [116]

Answer: <em>The values of......</em>

Step-by-step explanation:

Given function is: $\left \{ {{f(x)= \frac{1}{4}x^2 -4, if x\neq -2} \atop {=-1, if x=-2}} \right.$

For $f(-5),$ the value of $x$ is -5, which is not equal to -2.

So, $f(-5)= \frac{1}{4}(-5)^2 -4 = \frac{1}{4}(25)-4 =\frac{25}{4}-4=\frac{25-16}{4}=\frac{9}{4}$

For $f(-2),$ the value of $x$ is -2.

So, $f(-2)= -1$

For $f(4),$ the value of $x$ is 4, which is not equal to -2.

So, $f(4)=\frac{1}{4}(4)^2 -4 =\frac{1}{4}(16)-4 =4-4=0$

5 0

4 years ago

Below are survival times (in days) of 13 guinea pigs that were injected with a bacterial infection in a medical study:

tresset_1 [31]

Outliers are data that are relatively far from other data elements.

The dataset has an outlier and the outlier is 120

The dataset is given as:

91 83 84 79 91 93 95 97 97 120 101 105 98

Sort the dataset in ascending order

79 83 84 91 91 93 95 97 97 98 101 105 120

<h3>The lower quartile (Q1)</h3>

The Q1 is then calculated as:

$Q1 = \frac{N +1}{4}th$

So, we have:

$Q1 = \frac{13 +1}{4}th$

$Q1 = \frac{14}{4}th$

$Q1 = 3.5th$

This is the average of the 3rd and the 4th element

$Q1 = \frac{1}{2} \times (84 + 91)$

$Q1 = 87.5$

<h3>The upper quartile (Q3)</h3>

The Q3 is then calculated as:

$Q3 = 3 \times \frac{N +1}{4}th$

So, we have:

$Q3 = 3 \times \frac{13 +1}{4}th$

$Q3 = 3 \times 3.5th$

$Q3 = 10.5th$

This is the average of the 10th and the 11th element.

$Q_3 =\frac12 \times (98 + 101)$

$Q_3 =99.5$

<h3>The interquartile range (IQR)</h3>

The IQR is then calculated as:

$IQR = Q_3 -Q_1$

$IQR = 99.5 - 87.5$

$IQR = 12$

Also, we have:

$IQR(1.5) = 12 \times 1.5$

$IQR(1.5) = 18$

<h3>The outlier range</h3>

The lower and the upper outlier range are calculated as follows:

$Lower = Q_1 - IQR(1.5)$

$Lower = 87.5- 18$

$Lower = 69.5$

$Upper = Q_3 + IQR(1.5)$

$Upper = 99.5 + 18$

$Upper = 117.5$

120 is greater than 117.5.

Hence, the dataset has an outlier and the outlier is 120

Read more about outliers at:

brainly.com/question/9933184

6 0

2 years ago

How in the heck do I do this?

Fudgin [204]

The measure of a triangle is 180 degrees. In other words the sum of the angles of a triangle is 180 degrees

To solve for x set all of the expressions of angles equal to 180 and isolate x

11x - 3 + 7x + 5 + 13x - 8 = 180

31x + (- 6 + 6) = 180 + 6

31x/31 = 186 / 31

x = 6

To find the measure of each angle plug 6 into the x into each individual expression

Hope this helped!

6 0

4 years ago

The sum of two consecutive odd integers is 72 what are the integers

Yakvenalex [24]

The answer would be x + x + 2 = 72. Combine like terms so that 2x + 2 = 72. 2x = 70 and x = 35.

5 0

4 years ago

What percent of 25 is 12?<br><br> Enter your answer in the box.

RSB [31]

12/25=.48

.48 move the decimal two places

48%

3 0

4 years ago

Read 2 more answers