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Sliva [168]
2 years ago
10

A chess tournament was being held. This single-elimination tournament (in which paired competitors

Mathematics
1 answer:
Sergeeva-Olga [200]2 years ago
5 0

Answer:

A total of 15 matches were played.

Step-by-step explanation:

To determine the number of matches that were played in the chess tournament, knowing that there are 16 participants who face each other in a tournament of direct elimination, the following logical reasoning must be carried out:

In the first round there are 16 players, so being matches between 2 players, there are 8 matches (16/2). In the second round, applying the same reasoning and taking into account that there are only 8 players left, since the others have been eliminated, there are 4 matches (8/2). The same in the semifinals, where there are 2 games (4/2), and finally, the final to a single game.

Therefore, since 8 + 4 + 2 + 1 equals 15, the number of matches played in the tournament is 15.

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Step-by-step explanation:

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1) f(x) + g(x)

= 7√x + 4 + 2√x - 2

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Hope this helps!
5 0
3 years ago
If x Is a real number such that x3 = 64, the x2 + x equals what?
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