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3 years ago

I need help i need to Write 1.005 as a mixed number?

Mathematics

1 answer:

Thepotemich [5.8K]3 years ago

4 0

Answer:

1.005 as a mixed number is 1 5/1000

Step-by-step explanation:

if it's not that then it's 1 and 5

hope it helps

mark me brainliest pls

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How do you show 28 X 20 on a visual model (pls show with dots) (ASAP)

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3 years ago

Find the surface area of the cylinder. Round your answer to the nearest tenth.

kirill [66]

Given:

Height of cylinder = 12 cm

Diameter of cylinder = 6 cm

To find:

Surface area of the cylinder

Solution:

Radius = 6 ÷ 2 = 3 cm

Surface area formula:

$SA=2\pi r^2+2 \pi rh$

Substitute the given values.

$SA=2\times3.14 \times3^2+2\times3.14 \times3 \times12$

$=56.52+226.08$

= 286.2 cm²

The surface area of the cylinder is 286.2 cm².

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3 years ago

A store employee conducted a survey of 390 randomly selected customers. According to the survey, 180 of the customers often use

shusha [124]

You do 390/100 = 180/x then 390×X=390X
180×100=18000
390X=18000
390X÷390=X
18000÷390=46.15384615=46%

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4 years ago

Read 2 more answers

100 POINTS??? HELP ME ASAP

Katarina [22]

Answer:

Step-by-step explanation:

Double the first equation and get 2x + 2y = 300 (1). Call the second equation 2x + 5y = 405 (2). Calculate (2) - (1) to get 3y = 105, so y = 35.

5 0

3 years ago

Read 2 more answers

The mean weight of the seven linebackers was 236 pounds. The first six linebackers weighed 215lb, 305lb, 265lb, 196lb, 221lb, an

Nadya [2.5K]

Answer:

The weight of the seventh linebacker is = 214 lb.

Step-by-step explanation:

Given:

Mean of 7 linebackers = 236 lb

The weights of first 6 linebackers are:

215 lb, 305 lb, 265 lb, 196 lb, 221 lb and 236 lb

To find the weight of seventh linebacker.

Solution:

Let the weight of the seventh linebacker be = $x$

The mean of 7 line backers will be given as:

⇒ $\frac{215+305+265+196+221+236+x}{7}$

The mean of the 7 linebackers is given = 236 lb

Thus, the equation to find $x$ will be :

$\frac{215+305+265+196+221+236+x}{7}=236$

Simplifying.

$\frac{1438+x}{7}=236$

Multiplying both sides by 7.

$7.\frac{1438+x}{7}=236(7)$

$1438+x=1652$

Subtracting both sides by 1438.

$1438-1438+x=1652-1438$

∴ $x=214$

Thus, the weight of the seventh linebacker is = 214 lb.

7 0

3 years ago