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Examine the data below for a stalk of corn. Logarithmic regression Use logarithmic regression to find an equation of the form y

masya89 [10]

The value of a and b for the data values of stalk of corn using the logarithmic regression is -76.2038 and 37.6735 respectively.

<h3>What is logarithmic regression?</h3>

Logarithmic regression is a type of regression which is used to model the statement in which the growth or decay initially at rapid rate, and then slow down with respect to time.

The data of the table for the day and height of the stalk of corn is listed below.

Day (x) 9 12 22 40

Height (y) in 5 17 45 60

Mean of x values,

$m_x=\dfrac{9+12+22+40}{4}\\m_x=17.5581$

Mean of y values,

$m_y=\dfrac{5+17+45+60}{4}\\m_y=31.75$

For the above table, the value of correlation coefficient is 0.99133. For these values, the logarithmic regression can be given as,

$y = -76.2038+37.6735\ln(x)$

Compare it with the following logarithmic regression equation, we get

$y = a+b\ln(x)$

$a=-76.2038\\b=37.6735$

Hence, the value of a and b for the data values of stalk of corn using the logarithmic regression is -76.2038 and 37.6735 respectively.

Learn more about the logarithmic regression here;

brainly.com/question/25226042

5 0

2 years ago

Please answer this question ASAP. What is the slope of the line between the following points:

11111nata11111 [884]

A. -5/3 and b -9/7. the formula is y2-y1 and x2-x1

6 0

3 years ago

Janie receives R150 pocket money per month. In the new year his mother increase his pocket money in the ratio 6:5. Calculate Jan

dimaraw [331]

Answer:

Janies' monthly pocket money is $180.

Step-by-step explanation:

Janies' adjusted monthly pocket money:

Initial pocket money = $150

Ratio of new pocket money = 6:5

Let his new pocket money be represented by x,

x:$150 = 6:5

$150 x 6 = x (5)

$900 = 5x

x = $\frac{900}{5}$

x = $180

Therefore, Janies' monthly pocket money is $180.

6 0

3 years ago

You are competing in a race. The table shows the times from last year's race. You want your time to be last year's median time w

olasank [31]

Answer:

28 ≤ x ≤40

Step-by-step explanation:

Arrange the data from the smallest to the largest

26, 27, 28,32, 32, 33, 35, 36, 38, 40,42,48

Identify the median value

26, 27, 28,32, 32, 33, 35, 36, 38, 40,42,48

Getting the median

(33+35)/2 = 68/2 = 34 minutes

You want your time to be last year's median time with an absolute deviation of at most 6 minutes

This mean ±6 minutes, hence this will be 34 ± 6

34+6=40 and 34-6=28

The inequality will be 28 ≤ x ≤40

7 0

3 years ago

Read 2 more answers

Find the minimum and maximum value of the function on the given interval by comparing values at the critical points and endpoint

Kitty [74]

Answer:

maximum: y = 1

minimum: y = 0.

Step-by-step explanation:

Here we have the function:

y = f(x) = √(1 + x^2 - 2x)

we want to find the minimum and maximum in the segment [0, 1]

First, we evaluate in the endpoints, which are 0 and 1.

f(0) =√(1 + 0^2 - 2*0) = 1

f(1) = √(1 + 1^2 - 2*1) = 0

Now let's look at the critical points (the zeros of the first derivate)

To derivate our function, we can use the chain rule:

f(x) = h(g(x))

then

f'(x) = h'(g(x))*g(x)

Here we can define:

h(x) = √x

g(x) = 1 + x^2 - 2x

Then:

f(x) = h(g(x))

f'(x) = 1/2*( 1 + x^2 - 2x)*(2x - 2)

f'(x) = (1 + x^2 - 2x)*(x - 1)

f'(x) = x^3 - 3x^2 + x - 1

this function does not have any zero in the segment [0, 1] (you can look it in the image below)

Thus, the function does not have critical points in the segment.

Then the maximum and minimum are given by the endpoints.

The maximum is 1 (when x = 0)

the minimum is 0 (when x = 1)

7 0

3 years ago