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3 years ago

How to solve f(x)=2x+1 when x=a?

Mathematics

2 answers:

Lina20 [59]3 years ago

4 0

Answer:

2a+1

f(a)=2a+1

so, the answer u get is 2a+1

Anika [276]3 years ago

3 0

f(x)=2x+1

$\\ \bull\tt\looparrowright f(a)$

$\\ \bull\tt\looparrowright 2(a)+1$

$\\ \bull\tt\looparrowright 2a+1$

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5. Find the discriminant of 15x2 = 4x – 1 and describe

diamong [38]

Answer:

a) The discriminant of the equation = - 44

b)The nature of the roots will be imaginary.

c) $x = \frac{2 +\sqrt{11} i}{15} or, x = \frac{2 - \sqrt{11} i}{15}$

Step-by-step explanation:

Here, the given expression is $15x^{2} = 4x -1$

or, $15x^{2} - 4x + 1 = 0$

Now the discriminant (D) of a quadratic equation $ax^{2} +b x + c = 0$

D = $b^{2} - 4ac = (-4)^{2} - 4(15) (1) = 16 - (60) = -44$

Hence, the discriminant of the equation = - 44

As D< 0, so the roots will be imaginary.

Now,by quadratic formula : $x = \frac{-b \pm \sqrt{b^{2} - 4ac} }{2a}$

So, here $x = \frac{-(-4) \pm \sqrt{D} }{2a} = \frac{4 \pm \sqrt{(-44 )} }{30}$

So, either $x = \frac{4 + \sqrt{(-44 )} }{30} or, x = \frac{4 - \sqrt{(-44 )} }{30}$

or, $x = \frac{2 +\sqrt{11} i}{15} or, x = \frac{2 - \sqrt{11} i}{15}$

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3 years ago

What is the square root of -1?

lys-0071 [83]

Answer:

$i$

Step-by-step explanation:

<u>Step 1: Find the square root of -1</u>

<u /> $\sqrt{-1}$

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$i$

Answer: $i$

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How to solve f(x)=2x+1 when x=a?​

How to solve f(x)=2x+1 when x=a?