What is 1.7 x 10^-3 in standard form? Thanks!

Does anyone want to talk

muminat

Answer:

Yesssssss im heree :)))

3 0

2 years ago

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____ is necessary because researchers in the social sciences almost never have enough resources — time or money — to collect inf

Tanya [424]

Answer:

Sampling is necessary because researchers in the social sciences almost never have enough resources — time or money — to collect information about the entire set of subjects of interest to them.

Step-by-step explanation:

Sampling is done because you usually cannot gather data from the entire population. Even in relatively small populations, the data may be needed urgently, and including everyone in the population in your data collection may take too long.

4 0

2 years ago

D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x

MA_775_DIABLO [31]

The solution depends on the value of $k$ . To make things simple, assume $k>0$ . The homogeneous part of the equation is

$\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0$

and has characteristic equation

$r^2-16k=0\implies r=\pm4\sqrt k$

which admits the characteristic solution $y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}$ .

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be $y_p=ae^{4x}+be^x$ . Then

$\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x$

So you have

$16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x$
$(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x$

This means

$16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}$
$b(1-16k)=30\implies b=\dfrac{30}{1-16k}$

and so the general solution would be

$y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x$

8 0

2 years ago

A survey of 25 grocery stores revealed that the mean price of a gallon of milk was $2.98, with a standard error of $0.10. What i

Gnesinka [82]

Answer:

95% confidence interval: (2.784,3.176)

Step-by-step explanation:

We are given the following information in the question:

Sample size, n = 25

Sample mean = $2.98

Standard error = $0.10

Alpha = 0.05

95% confidence interval:

$\mu \pm z_{critical}(\text{Standard error})$

Putting the values, we get,

$z_{critical}\text{ at}~\alpha_{0.05} = 1.96$

$2.98 \pm 1.96(0.10) = 2.98 \pm 0.196 = (2.784,3.176)$

5 0

2 years ago

Need all these tomorrow!!!!! thank you all soooooOOOOOOooOoOOooOOoO much!!!!!

nordsb [41]

1.) 6% of 38 1% of 38 = 3.8 ( you just move the decimal placement over by one. 1% * 6 = 6% 3.8 * 6 = 6% 3.8 * 6 = 22.8 6% =22.8 2.) 5% of 90 90/5 = 5% 90/5 = 18 18 = 5% 3.) 15/5 = 9/x 15/5 = 3 3 = 9/x (nine divided by ? is three?....3!) 3 = 9/x(3) 3 = 9/3 3 = 3 x = 3 4.) 1/12 = .8/x Multiply each side by ten. 1/12 * 10 = 5/6 .8/x * 10 = 8/x 5/6 = 8/x Cross Multiply (switch the second numbers around) 5x = 6*8 Simplify 5x = 48 Divide both sides by 5 to get x by itself 5x/5 = x 48/5 = 9.6 *Whoo last problem lol* 5.) A three liter bottle costs $2.97 what is the unit rate. Well the unit is the object we're talking about, in this case a liter bottle. The unit rate is how much it costs or is per unit. Now that that's out of the way... 3L = 2.97 Like the other problems we want to get x by itself, so we'll divide by three) 3L/3 = L 2.97/3 = .99 L = .99 The Unit Rate is $0.99 per liter bottle. Hope this helped :)

3 0

3 years ago