PLEASE HELP WITH THIS MATH QUESTION!!..

Paul wants to visit his aunt who lives 300 miles away from his house. He drives his car at about 50 miles an hour. If X represen

anyanavicka [17]

Answer:

It would take 6 hours.

An equation for that could be: 50x = 300 (X is how long it would take)

So 50 mph• X (time spent) = 300 miles

You didn't give me any scatterplots to look at so I can't help you with that sorry

3 0

3 years ago

Task 2 a. Do some research and find a city that has experienced population growth. Determine its population on January 1st of a

Galina-37 [17]

Exponential functions are functions defined by y = ab^x, where a represents the initial value, and b represents the rate

<h3>The equation of a city that has experienced a population growth</h3>

The initial population of the city is 10000, and the growth rate of the population is 4%.

So, the exponential equation is:

$y = 10000 * 1.04^x$

<h3>The equation of a city that has experienced a population decline</h3>

The initial population of the city is 12000, and the decay rate of the population is 3%.

So, the exponential equation is:

$y = 12000* 0.97^x$

<h3>The similarities in the equations</h3>

The similarity in both equations is that, they both represent exponential function.

<h3>The year the population of city A exceeds B</h3>

In (a) and (b), we have:

$y = 10000 * 1.04^x$ ---- city A

$y = 12000* 0.97^x$ --- city B

When city A exceeds city B, we have the following inequality

$10000 * 1.04^x > 12000 * 0.97^x$

Divide both sides by 10000

$1.04^x > 1.2 * 0.97^x$

Divide both sides by 0.97^x

$(\frac{1.04}{0.97})^x > 1.2$

$1.07^x > 1.2$

Take the natural logarithm of both sides

$\ln(1.07)^x > \ln(1.2)$

This gives

$x\ln(1.07) > \ln(1.2)$

Solve for x

$x > \frac{\ln(1.2)}{\ln(1.07)}$

$x > 2.69$

This means that, the population of city A will exceed city B after 3 years

<h3>The year the population of city A will be at least twice of city B</h3>

In (a) and (b), we have:

$y = 10000 * 1.04^x$ ---- city A

$y = 12000* 0.97^x$ --- city B

When city A is at least twice city B, we have the following inequality

$10000 * 1.04^x \ge 2 * 12000 * 0.97^x$

$10000 * 1.04^x \ge 24000 * 0.97^x$

Divide both sides by 10000

$1.04^x \ge 2.4 * 0.97^x$

Divide both sides by 0.97^x

$(\frac{1.04}{ 0.97})^x \ge 2.4$

$1.07^x \ge 2.4$

Take the natural logarithm of both sides

$\ln(1.07)^x \ge \ln(2.4)$

This gives

$x\ln(1.07) \ge \ln(2.4)$

Solve for x

$x\ge \frac{\ln(2.4)}{\ln(1.07) }$

$x\ge 12.9$

This means that, the population of city A will be at least twice city B after 13 years

Read more about exponential functions at:

brainly.com/question/11464095

3 0

3 years ago

Find the perimeter of a quadrilateral with vertices at C (-1,2), D (-2,-1), E (2,-2), and F (1,1). Round to the nearest hundredt

stealth61 [152]

To answer, find the distance from point C to D, point D to E, point E to F, and point F to C. The formula for the distance is,
d = sqrt ((x2 - x1)² + (y2 - y1)²)
Point C to D d1 = sqrt ((-3 - -2)² + (1 - 4)²) = 3.16 units
Point D to E d2 = sqrt ((1 - -3)² + (0 - 1)²) = 4.12 units
Point E to F d3 = sqrt ((-1 - 1)² + (2 - 0)²) = 2.83 units
Point F to C d4 = sqrt ((-1 - -2)² + (2 - 4)²) = 2.23 units
Then, add up all the distances and the answer is 12.34 units. The closest answer is letter D. Credit:Meerkat

7 0

3 years ago

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Need Help ....!!!

postnew [5]

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