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sp2606 [1]
3 years ago
13

Bill has some counter in a bag.

Mathematics
1 answer:
andrew11 [14]3 years ago
8 0

9514 1404 393

Answer:

  4

Step-by-step explanation:

The 10 non-yellow counters in the bag represent 5/7 of the total number of counters, c.

  10 = (5/7)c

  10(7/5) = c = 14

There are 14 counters in the bag, of which 14-10 = 4 are yellow.

_____

<em>Alternate solution</em>

Let y represent the number of yellow counters in the bag. The probability of drawing a yellow counter is the number of yellow counters divided by the total number of counters:

  y/(y +3 +7) = 2/7

Multiply both sides of this equation by 7(y+10) to get ...

  7y = 2(y +10)

  7y = 2y +20 . . . . eliminate parentheses

  5y = 20 . . . . . . . . subtract 2y

  y = 20/5 = 4 . . . . divide by the coefficient of y

There are 4 yellow counters in the bag before any are taken.

__

<em>Another alternate solution</em>

If the probability of yellow is 2/7, the ratio of yellow (y) to non-yellow is ...

  yellow : non-yellow = 2 : (7-2) = 2 : 5 = y : (3+7) = y : 10 = 4 : 10

  ⇒ y = 4

There are 4 yellow counters in the bag.

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Step-by-step explanation:

It is given in the question that K is the midpoint of JL.

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