Answer:
First option
Explanation:
If the ball is running in a circular motion then its velocity <em>v</em> will be tangency to the circular path.
In this problem the centripetal force that allows the circular movement is the tension <em>T</em> of the rope to which the ball is tied, if the child releases the rope then this tension becomes equal to zero and the circular movement is interrupted.
As the speed <em>v</em> of the ball is always tangential to the circumference at any point of the same, then at the instant in which the rope is released, the ball will follow the same trajectory that it had at that moment, that is, tangential to the circumference.
Observe the attached image.
Therefore the answe is: tangent to the circle
The force used to kick the ball is 1000N
The mass of the ball is 0.8 kg
Time is 0.8 seconds
Therefore the velocity can be calculated as follows
F= Mv-mu/t
1000= 0.8(v) - 0.8(0)/0.8
1000= 0.8v- 0.8/0.8
Cross multiply both sides
1000(0.8) = 0.8v
800= 0.8v
divide both sides by the coefficient of v which is 8
800/0.8= 0.8v/0.8
v= 1000m/s
Hence the velocity is 1000m/s
Answer:
The index refraction of the unknown material is 1.08
Explanation:
Light has characteristics of a wave. When light travels or propagates through two media with different index of refraction, the light will bend or will change its speed.
Using Snells' law which is stated mathematically as:
n1Sintheta1 = n2Sinthetha2
Given:
n1 = 1.17
Theta1 = 40.1° = angle of incidence
Theta2 = 36.3° = angle of refraction
n2 = unknown
Substituting into the equation
n1Sin40.1 = 1.17Sin36.3°
0.6441n1 = 0.6937
n1 = 0.6937/0.6441
n1 = 1.08
Answer:
Option B, Fix the piston in place so the volume of the pas remains constant
Explanation:
As we know
The effect on variable due to another variable can be studied by keeping the third variable constant.
Hence, in order the study the variation of temperature with pressure or vice versa, the volume needs to fixed at a certain value.
Hence, option B is correct
-- The acceleration due to gravity is 32.2 ft/sec² . That means that the
speed of a falling object increases by an additional 32.2 ft/sec every second.
-- If dropped from "rest" (zero initial speed), then after falling for 4 seconds,
the object's speed is (4.0) x (32.2) = <em>128.8 ft/sec</em>.
-- 128.8 ft/sec = <em>87.8 miles per hour</em>
Now we can switch over to the metric system, where the acceleration
due to gravity is typically rounded to 9.8 meters/sec² .
-- Distance = (1/2) x (acceleration) x (time)²
D = (1/2) (9.8) x (4)² =<em> 78.4 meters</em>
-- At 32 floors per 100 meters, 78.4 meters = dropped from the <em>25th floor</em>.
The 5 points are certainly appreciated, but I do wish they were Celsius points.