Answer:
B: Y=1/2×+2 I think that's it
Answer:
24
Step-by-step explanation:
I have had this question before I know the answer
What we have so far:
Kinetic energy = 0. The reason behind that is because the beam is not moving at a height of 40m.
Gavity, g = 9.8m/s²
Height = 40m
Potential energy = mgh; this is equal to 0 because m, stands for mass and in this problem, we do not have a value for the mass of the beam. Hence, 0 x 9.8m/s² x 40m = 0. Potential energy = 0.
Solution:
We will use the equation of Total energy:
TE = potential energy + kinetic energy
TE = 0 + 0
∴ TE = 0
The answer is: Assuming no air resistance, the total energy of the beam as it hits the ground is 0.
Answer:
11.1714
Step-by-step explanation:
Just use a calculator! :)
Answer:
All Real Numbers
Step-by-step explanation:
g(t) = (t − 7)(t + 6)
= t^2 - t - 42
This is a parabola which opens upwards.
The domain is All Real Numbers