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3 years ago

which field or study (organic chemistry or inorganic chemistry) includes the study of the properties and preparation of chalk?

Chemistry

1 answer:

jeka57 [31]3 years ago

3 0

Answer:the answer is d

Explanation:

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How does matter and energy cycle through an ecosystem?

Ainat [17]

A Cellular respiration alone
Your welcome

6 0

2 years ago

Consider the reaction 2N2(g) O2(g)2N2O(g) Using the standard thermodynamic data in the tables linked above, calculate Grxn for t

ratelena [41]

Answer:

$\Delta G^0 _{rxn} = 207.6\ kJ/mol$

ΔG ≅ 199.91 kJ

Explanation:

Consider the reaction:

$2N_{2(g)} + O_{2(g)} \to 2N_2O_{(g)}$

temperature = 298.15K

pressure = 22.20 mmHg

From, The standard Thermodynamic Tables; the following data were obtained

$\Delta G_f^0 \ \ \ N_2O_{(g)} = 103 .8 \ kJ/mol$

$\Delta G_f^0 \ \ \ N_2{(g)} =0 \ kJ/mol$

$\Delta G_f^0 \ \ \ O_2{(g)} =0 \ kJ/mol$

$\Delta G^0 _{rxn} = 2 \times \Delta G_f^0 \ N_2O_{(g)} - ( 2 \times \Delta G_f^0 \ N_2{(g)} + \Delta G_f^0 \ O_{2(g)})$

$\Delta G^0 _{rxn} = 2 \times 103.8 \ kJ/mol - ( 2 \times 0 + 0)$

$\Delta G^0 _{rxn} = 207.6\ kJ/mol$

The equilibrium constant determined from the partial pressure denoted as $K_p$ can be expressed as :

$K_p = \dfrac{(22.20)^2}{(22.20)^2 \times (22.20)}$

$K_p = \dfrac{1}{ (22.20)}$

$K_p$ = 0.045

$\Delta G = \Delta G^0 _{rxn} + RT \ lnK$

where;

R = gas constant = 8.314 × 10⁻³ kJ

$\Delta G =207.6 + 8.314 \times 10 ^{-3} \times 298.15 \ ln(0.045)$

$\Delta G =207.6 + 2.4788191 \times \ ln(0.045)$

$\Delta G =207.6+ (-7.687048037)$

$\Delta G =$ 199.912952 kJ

ΔG ≅ 199.91 kJ

7 0

4 years ago

NEED HELP ASAP; PLEASE SHOW YOUR WORK.

Sindrei [870]

Answer:

n = 0.3 mol

Explanation:

Given data:

Volume of gas = 8.0 L

Temperature of gas = 45 °C (45+273 = 318 K)

Pressure of gas = 0.966 atm

Moles of gas present = ?

Ideal gas constant = R = 0.021 atm.L/mol.K

Solution:

Formula:

PV = nRT

P = Pressure

V = volume

n = number of moles

R = ideal gas constant

T = temperature

Now we will put the values:

0.966 atm × 8 L = n × 0.0821 atm.L/mol.K × 318 K

7.728 atm.L = n × 26.12 atm.L/mol

7.728 atm.L / 26.12 atm.L/mol = n

n = 0.3 mol

5 0

4 years ago

Hello can somone help me ?

zalisa [80]

$174 \; \text{protons} / (29 \; \text{copper atoms} \cdot \text{proton}^{-1}) = 6 \; \text{copper atoms}$

Thus 174 protons would make at most 6 copper atoms. However, it would take 174 extra electrons (29 per atom) and even more neutrons than that to construct neutral copper atoms with stable nuclei.

7 0

3 years ago

Please answer 14 will give brainliest

rosijanka [135]

Answer:

I think it's alkali metals

4 0

3 years ago

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