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tensa zangetsu [6.8K]
3 years ago
14

26. 8 g of ammonium chloride is dissolved in water to make a 0. 25 L solution. What is the molarity of the solution?

Chemistry
1 answer:
pishuonlain [190]3 years ago
6 0

Answer: 0.5 M

Explanation:

Ammonium chloride has a gram formula mass of 53.49 g/mol, so 26.8 grams of ammonium chloride is 26.8/53.49 = 0.501 mol.

So since molarity = (moles of solute)/(liters of solution), the answer is 0.501 / 0.25 = 0.5 M

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Answer:

Highest speed: He

Lowest speed: CO2

Explanation:

The rms speed (average speed) of the molecules/atoms in an ideal gas is given by:

v=\sqrt{\frac{3RT}{M}}

where

R is the gas constant

T is the absolute temperature of the gas

M is the molar mass of the gas, which is the mass of the gas per unit mole

From the equation, we see that at equal temperatures, the speed of the molecules in the gas is inversely proportional to the molar mass: the higher the molar mass, the lower the speed, and vice-versa.

In this problem, we have 5 gases:

(CO2) (O2) (He) (N2) (CH4)

Their molar mass is:

CO2: 44 g/mol

O2: 16 g/mol

He: 4 g/mol

N2: 14 g/mol

CH4: 16 g/mol

The gas with lowest molar mass is Helium (He): therefore, this is the gas with greatest average speed.

The gas with highest molar mass is CO2: therefore, this is the gas with lowest average speed.

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4 years ago
Write one word for the following short form of an element​
ra1l [238]

Answer:

symbol?

Explanation:

6 0
3 years ago
Which incorrect aspect of Rutherford’s model was fixed by Bohr’s model?
dolphi86 [110]

Answer:

Some things that were wrong with Rutherford's model were that the orbiting electrons should give off energy and eventually spiral down into the nucleus, making the atom collapse. Bohr proposed his quantized shell model of the atom to explain how electrons can have stable orbits around the nucleus. To remedy the stability problem, Bohr modified the Rutherford model by requiring that the electrons move in orbits of fixed size and energy.

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3 years ago
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Answer:

V = 14.2 L

Explanation:

Given data:

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V = nRT/P

V = 0.632 mol ×0.0821 atm.L/ mol.K × 273 K / 1 atm

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