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3 years ago

Within the atmosphere as the altitude increases?

Chemistry

2 answers:

Troyanec [42]3 years ago

6 0

What is the question?

marta [7]3 years ago

3 0

Answer:

Within the atmosphere, as altitude increases,

A.air pressure stays the same.

B.air becomes heavier.

C.air pressure decreases. The answer.

D.air pressure increases.

Explanation:

That's the question. AND Pressure with Height: pressure decreases with increasing altitude. The pressure at any level in the atmosphere may be interpreted as the total weight of the air above a unit area at any elevation. At higher elevations, there are fewer air molecules above a given surface than a similar surface at lower levels. Hope that helps. This means the answer is C.

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Where would electrons in the d sub level be found

notka56 [123]

Answer:

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So the answer is "In any energy levels ≥ 3"

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3 years ago

What is the molarity of 42.1 g of AgNO3 dissolved in 1.75 L of solution?

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3 years ago

The final temperature of the gas is <br> K.

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4 years ago

Read 2 more answers

Which describes the letter that belongs where the question mark is?

Evgesh-ka [11]

Explanation:

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3 years ago

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B. if 6.73 g of na2co3 is dissolved in enough water to make 250. ml of solution, what is the molar concentration of sodium carbo

BARSIC [14]

Answer:- $[Na_2CO_3]=0.254M$ , $[Na^+]=0.508 M$ , $[CO_3^2^-]=0.254M$

Solution:- We are asked to calculate the molarity of sodium carbonate solution as well as the sodium and carbonate ions.

Molarity is moles of solute per liter of solution. We have been given with 6.73 grams of sodium carbonate and the volume of solution is 250.mL. Grams are converted to moles and mL are converted to L and finally the moles are divided by liters to get the molarity of sodium carbonate.

Molar mass of sodium carbonate is 105.99 gram per mol. The calculations for the molarity of sodium carbonate are shown below:

$\frac{6.73gNa_2CO_3}{250.mL}(\frac{1mol}{105.99g})(\frac{1000mL}{1L})$

= $0.254MNa_2CO_3$

So, molarity of sodium carbonate solution is 0.254 M.

sodium carbonate dissociate to give the ions as:

$Na_2CO_3(aq)\rightarrow 2Na^+(aq)+CO_3^2^-$

There is 1:2 mol ratio between sodium carbonate and sodium ion. So, the molarity of sodium ion will be two times of sodium carbonate molarity.

$[Na^+]=2(0.254M)$ = 0.508 M

There is 1:1 mol ratio between sodium carbonate and carbonate ion. So, the molarity of carbonate ion will be equal to the molarity of sodium carbonate.

$[CO_3^2^-]=0.254M$

5 0

4 years ago