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3 years ago

Find the amount of interest on $35,000 at 9.72% compounded monthly for 32 months

Mathematics

1 answer:

zhannawk [14.2K]3 years ago

4 0

9514 1404 393

Answer:

$10,308.92 interest earned

Step-by-step explanation:

The account balance is given by ...

A = P(1 +r/12)^n

where principal P earns interest at annual rate r compounded monthly for n months. In this case, the balance would be ...

A = $35,000(1 +0.0972/12)^32 = $45,308.92

The interest earned is the excess of the balance over the original investment:

interest = $45,308.92 -35,000 = $10,308.92

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What is the binomial expansion of (x + 2y)7?

borishaifa [10]

<h2>Thus, the required "option 4)" is correct.</h2>

Step-by-step explanation:

We find,

$(x+2y)^7$

To find, the binomial expansion of of $(x+2y)^7$ = ?

We know that,

$(x+y)^{n} =^nC_0x^n+^nC_1x^{n-1}y+nC_2x^{n-2}y^2+nC_3x^{n-3}y^3+...+^nC_ny^n$

∴ $(x+2y)^7$

Here, n = 7, x = x and y = 2y

$(x+2y)^7$ = $^7C_0x^7+^7C_1x^{7-1}(2y)+^7C_2x^{7-2}(2y)^2+^7C_3x^{7-3}(2y)^3+^7C_4x^{7-4}(2y)^4+^7C_5x^{7-5}(2y)^5+^7C_6x(2y)^6+(2y)^7$ $=x^7+7x^{6(2y)+21x^{5}4y^2+35x^{4}8y^3+^35x^{3}16y^4+21x^{2}32y^5+7x64y^6+128y^7$

$=x^7+14x^{6}y+84x^{5}y^2+280x^{4}y^3+560x^{3}y^4+672x^{2}y^5+448xy^6+128y^7$

∴ The binomial expansion of of $(x+2y)^7$

$=x^7+14x^{6}y+84x^{5}y^2+280x^{4}y^3+560x^{3}y^4+672x^{2}y^5+448xy^6+128y^7$

Thus, the required "option 4)" is correct.

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3 years ago

Clarisvaudney tem 12 anos. Seu primo é 50% mais novo.Qual é a soma da idade dos dois?

Nitella [24]

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12/2=6
6+12=18

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3 years ago

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ivann1987 [24]

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4 years ago

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saveliy_v [14]

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Step-by-step explanation:

Solve for Y if X =0

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