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elena-14-01-66 [18.8K]
3 years ago
14

A square has an area of 100m2 (100m squared)

Mathematics
1 answer:
Nonamiya [84]3 years ago
6 0
Since we know that the area is 100 and we are dealing with a square, that means that all sides are equal. We know that the sides are all 10 because 10*10= 100.

To find the perimeter, we add up all the sides: 10+10+10+10 = 40m
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Find the measure of the exterior angle. *
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Step-by-step explanation:

✧ \underline{ \underline{ \large{ \tt{S \: O \: L \: U \: T \: I \: O \: N}}} }:

  • Set up an equation and solve for x :

⋆ \large{ \bf{(4x + 9) \degree = 2x \degree + (3x - 12) \degree}} [ Exterior angle is always equal to the sum of two non - adjacent interior angles ]

~Remove the unnecessary brackets

⟶ \large{ \bf{4x \degree + 9 \degree = 2x \degree + 3x \degree - 12 \degree}}

~Add the like terms : 2x ° & 3x°

⟶ \large{ \bf{4x \degree + 9 \degree = 5x \degree - 12 \degree}}

~Move 4x to right hand side and change it's sign

~Similarly move 12 to left hand side and change it's sign

⟶ \large{ \bf{9 \degree + 12 \degree = 5x  \degree - 4x \degree}}

⟶ \large{ \bf{21 \degree = x \degree}}

⟶ { \large{ \bf{x  = 21 \degree}}}

  • Now , Substituting the value of x in (4x+9)° [ Exterior angle ]

⤿ \large{ \bf{4 \times 21 \degree + 9 \degree}} =  \boxed{93 \degree}

☥ \boxed{ \boxed{ \large{ \tt{Our \: Final \: Answer :  \boxed{ \underline { \tt{93\degree}}}}}}}

Hope I helped ! ツ

Have a wonderful day / night ! ♡

❅ Let me know if you have any questions regarding my answer! ❅

☞ \underline{ \underline{ \mathfrak{Carry \: On \: Learning}}} !! ✎

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

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