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WARRIOR [948]
3 years ago
10

Find the prime factorization of 504

Mathematics
1 answer:
BaLLatris [955]3 years ago
4 0
It's not a prime number but
Answer : 23 • 32 • 7
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Toni rides the Ferris wheel shown for 15 revolutions. A photo of a Ferris wheel has the diameter labeled fifty-six feet. Questio
NARA [144]

Answer:

a. 176 feet b. 2640 feet

Step-by-step explanation:

a. Since the diameter of the Ferris wheel is D = 56 feet, the distance Toni travels in one revolution is the circumference of the Ferris wheel, C = πD.

So C = 22/7 × 56 ft = 22 × 8 ft = 176 feet

b. The distance traveled in 15 revolutions is thus D' = 15 × distance of one revolution = 15 × 176 = 2640 feet

5 0
3 years ago
I need help with this!! What is the answer???!
Natalija [7]

Answer:

53

Step-by-step explanation:

Sum of interior angles of a pentagon = 540°

Therefore,

2x° +2x° + 3x° + 3x° + 10 = 540°

10x° + 10° = 540°

10x° = 540° - 10°

10x° = 530°

10x = 530

x = 530/10

x = 53

7 0
3 years ago
Solve.<br> -6&lt;3n+9&lt;21<br> Thanks!
almond37 [142]

Answer:

the answer you are looking for is -5<n<4

5 0
2 years ago
Read 2 more answers
Find the distance between the two points rounding to the nearest tenth (if necessary).
Virty [35]

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{3}~,~\stackrel{y_1}{6})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{9})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{(1-3)^2+(9-6)^2}\implies d=\sqrt{(-2)^2+3^2} \\\\\\ d=\sqrt{13}\implies d\approx 3.6056\implies \stackrel{\textit{rounded up}}{d=3.6}

4 0
3 years ago
Write a two-column proof. Given: line BD bisects angle CBE. Prove: angle ABD approximately equal to angle FBD.
ale4655 [162]

Answer:

The proof is derived from the summarily following equations;

∠FBE + ∠EBD = ∠CBA + ∠CBD

∠FBE + ∠EBD = ∠FBD

∠CBA + ∠CBD = ∠ABD

Therefore;

∠ABD ≅ ∠FBD

Step-by-step explanation:

The two column proof is given as follows;

Statement {}                                       Reason          

\underset{BD}{\rightarrow} bisects ∠CBE {}                            Given

Therefore;

∠EBD ≅ ∠CBD  {}                              Definition of angle bisector

∠FBE ≅ ∠CBA {}                                Vertically opposite angles are congruent

Therefore, we have;

∠FBE + ∠EBD = ∠CBA + ∠CBD {}     Transitive property

∠FBE + ∠EBD = ∠FBD {}                    Angle addition postulate

∠CBA + ∠CBD = ∠ABD {}                   Angle addition postulate

Therefore;

∠ABD ≅ ∠FBD        {}                          Transitive property.

3 0
3 years ago
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