If the length of a rectangle is 3m longer than its width, then:
L=W+3
Is the area really 154^2? Or is it 154m^2? If yes, then:
A=LW
154=(W+3)(W)
154=(W^2+3W)
0=W^2+3W-154
0=(W-11)(W+14)
This means either (W-11) or (W+14) is equal to zero so:
W=11 and W=-14
To find out let's substitute the numbers:
154=(11+3)(11)
154=154
Therefore, the width of the rectangle is 11m
First you need to add 2 to every part of the equation. So -14+2, -2+2, and 22+2. After that you need to divide every part by 6, -12/6, 6/6, 24/6 which gives you the answer; -2
153 don’t take my word for just but I hope this is a little helpful
63-x=62
Then subtract 62 and 63
-x=-1
x=1
