Select the equivalent expression (7^2 x 5^6)^4

(10.02)

ollegr [7]

<h2>Hello!</h2>

The answer is:

C. Cosine is negative in Quadrant III

Let's discard each given option in order to find the correct:

A. Tangent is negative in Quadrant I: It's false, all functions are positive in Quadrant I (0° to 90°).

B. Sine is negative in Quadrant II: It's false, sine is negative in positive in Quadrant II. Sine function is always positive coming from 90° to 180°.

C. Cosine is negative in Quadrant III. It's true, cosine and sine functions are negative in Quadrant III (180° to 270°), meaning that only tangent and cotangent functions will be positive in Quadrant III.

D. Sine is positive in Quadrant IV: It's false, sine is negative in Quadrant IV. Only cosine and secant functions are positive in Quadrant IV (270° to 360°)

Have a nice day!

6 0

3 years ago

While performing a vertical line test on a graph, you notice that the graph intercepts the vertical line twice. Which of the fol

MakcuM [25]

Answer:

The correct option is;

Because the vertical line intercepted the graph more than once, the graph is of a relation, but it is not a function

Step-by-step explanation:

Given that a function maps a given value of the input variable, to the output variable, we have that a relation that has two values of the dependent variable, for a given dependent variable is not a function

Therefore, a graph in which at one given value of the input variable, x, there are two values of the output variable y is not a graph of a function

With the vertical line test, if a vertical line drawn at any suitable location on the graph, intercepts the graph at more than two points, then the relationship shown on the graph is not a function.

6 0

3 years ago

How do you work out (7x+3)(7x-3)

spin [16.1K]

We can solve this using the FOIL method.

= (7x + 3)(7x - 3)

= (7x * 7x) + (7x * -3) + (3 * 7x) + (3 * -3)

= 49x - 21x + 21x - 9

= 49x - 9

Hope This Helped! Good Luck!

7 0

2 years ago

Given that 2y^3+by-cy+d,where b,c and d are constants,leaves a remainder R when divided by (y+1) , (y-2) and (2y-1). Find the va

Eddi Din [679]

The polynomial remainder theorem says that a polynomial p(x) leaves a remainder of p(k) when it's divided by x - k.

We're given that dividing p(y) = 2y³ + by² - cy + d leaves the same remainder R after dividing it by y + 1, y - 2, and 2y - 1. So we have

p(-1) = 2(-1)³ + b(-1)² - c(-1) + d = R

==> R = -2 + b + c + d

p(2) = 2(2)³ + b(2)² - c(2) + d = R

==> R = 16 + 4b - 2c + d

p(1/2) = 2(1/2)³ + b(1/2)² - c(1/2) + d = R

==> R = 1/4 + b/4 - c/2 + d

We're also given that y + 2 is a factor, which means dividing p(y) by it leaves no remainder, and so

p(-2) = 2(-2)³ + b(-2)² - c(-2) + d = 0

==> 0 = -16 + 4b + 2c + d

Solve the system of equations in boldface. You can eliminate d from the first 3 to first solve for b and c, then solve for d :

(-2 + b + c + d) - (16 + 4b - 2c + d) = R - R

-18 - 3b + 3c = 0

b - c = -6

(-2 + b + c + d) - (1/4 + b/4 - c/2 + d) = R - R

-9/4 + 3b/4 + 3c/2 = 0

b + 2c = 3

(b - c) - (b + 2c) = -6 - 3

-3c = -9

c = 3

b - 3 = -6

b = -3

-16 + 4(-3) + 2(3) + d = 0

d = 22

7 0

3 years ago

Plz help!

zloy xaker [14]

The factored expression is: 3(5n-6)
The GCF between 15 and 18 is 3. So you would divide both numbers by 3. That would leave you with 5 taking the place of 15 and 6 taking the place of 18. Then you would fill in the blanks. Three multiplied by the expression 5n-6 would give you your original expression of 15n-18.

8 0

3 years ago