Question

Ms.c is 6 1/3 feet tall, her brother is 6 5/6 feet tall. How much taller is her brother?

Answer 1

Answer:

1/2 feet ( 6 inches )

step by step explanation:

$Height \: of \: Ms.c \: = \: 6 \frac{1}{3} feet$

$Height \: of \: her \: brother = 6 \frac{5}{6}$

Therefore,

$Height \: of \: her \: brother \: more \: than \: him$

$= 6 \frac{5}{6} - 6\frac{1}{3}$

Let's bring it into improper fraction.

$6 \frac{1}{3} = \frac{6 \times 3 + 1}{3} = \frac{19}{3}$

$6 \frac{5}{6} = \frac{6 \times 6 + 5}{6} = \frac{41}{6}$

Now For subtracting improper fraction with different denominators we need to find the L.C.M of both the denominators.

We know that the L.C.M of both 3 and 6 is 6

So

$\frac{41}{6} = \frac{41 \times 1}{6 \times 1} = \frac{41}{6}$

$\frac{19}{3} = \frac{19 \times 2}{3 \times 2} = \frac{38}{6}$

Now we can subtract

$\frac{41}{6} - \frac{38}{6} = \frac{41 - 38}{6} = \frac{3}{6}$

Now we can even bring it into its lowest term

Like this

$\frac{3}{6} = \frac{3 \div 3}{6 \div 3} = \frac{1}{2}$

So the answer is

Mc.s brother is ½ feet taller than her.

Hope it helps you!!

#IndianMurga

Answer 2

$\Huge\boxed{\frac{1}{2}\ \textsf{feet}\ \Large\textsf{(6 inches)}}$

To solve this question, we simply need to subtract the two numbers.

$\displaystyle6\frac{5}{6}-6\frac{1}{3}$

We'll start by changing these into improper fractions to simplify things for now.

$\displaystyle\begin{aligned}(\frac{36}{6}+\frac{5}{6})&-(\frac{18}{3}+\frac{1}{3})\\\frac{41}{6}&-\frac{19}{3}\end{aligned}$

Now, we need to make these fractions share a common denominator. We'll do this by multiplying the second fraction by $2$. Keep in mind that whatever is done to the denominator must also be done to the numerator.

$\displaystyle\frac{41}{6}-\frac{19\cdot2}{3\cdot2}\\\frac{41}{6}-\frac{38}{6}$

Finally, subtract the numerators and keep the denominators.

$\displaystyle\frac{41-38}{6}\\\frac{3}{6}$

We can simplify this fraction by dividing both the numerator and the denominator by $3$.

$\displaystyle\frac{3\div3}{6\div3}\\\large\boxed{\frac{1}{2}}$