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3 years ago

Help me for points :)

Mathematics

1 answer:

Archy [21]3 years ago

8 0

1) associative
2) identity
3) commutative

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Find the indicated limit, if it exists. limit of f of x as x approaches 9 where f of x equals x plus 9 when x is less than 9 and

SVEN [57.7K]

Answer:

B. 18

Step-by-step explanation:

For the function

$f(x)=\left\{\begin{array}{l}x+9,\ \ x$

we can find the value of the function for all x that are very close to 9 but are less than 9 and for all values of x that are very close to 9 but are greater than 9.

1. For $x$

$\lim \limits_{x\rightarrow 9}f(x)=\lim \limits_{x\rightarrow 9}(x+9)=9+9=18$

2. For $x\ge 9:$

$\lim \limits_{x\rightarrow 9}f(x)=\lim \limits_{x\rightarrow 9}(27-x)=27-9=18$

So, limit exists and is equal to 18.

8 0

3 years ago

How can you use models to explain why 3.1 = 3.10

Andrej [43]

3.1 is like a example when it is hiding a zero behind it and you find this when you do a math problem and you don't put zero in front of a number like 100-89 you don't write "011" so that is why it is like that

4 0

2 years ago

I need help please reply quickly higher gcse question

nexus9112 [7]

Answer:

105 cm²

Step-by-step explanation:

The figure is composed of a rectangle and a triangle

area of rectangle = 15 × 6 = 90 cm²

area of triangle = $\frac{1}{2}$ bh ( b is the base and h the height )

Here b = 15 - 9 = 6 and h = 11 - 6 = 5 , thus

area of triangle = $\frac{1}{2}$ × 6 × 5 = 3 × 5 = 15 cm²

Total area = 90 + 15 = 105 cm²

5 0

3 years ago

Read 2 more answers

What is the shape of the cross-section formed when a plane containing line AC and line EH intersects this cube? What is the area

velikii [3]

Answer:

Cross section is a rectangle.

Area of cross section = 16 sqrt(2) = 22.63 sq. units (to 2 decimals)

Step-by-step explanation:

Given a cube.

top face ABCD is parallel and congruent to bottom face EFGH ........(1)

justified by the properties of cubes

Sides AE and CH are perpendicular to faces ABCD and EFGH ..........(2)

justified by the properties of cubes

Diagonals AC and EH are congruent ......................(3)

justified by (1), congruent top and bottom faces

Consider cross-section ACHE

AC is congruent and parallel to EH (1) & (3)

EA & HC are perpendicular to AC (2)

Therefore the quadrilateral ACHE is a rectangle.

Length of diagonal AC = sqrt(4^2+4^2) = 4 sqrt(2) ..........pythagoras theorem

AE = CH = DG = 4 properties of cube, all sides equal

Area of ACHE = 4* 4sqrt(2) = 16 sqrt(2) = 22.63 sq. units

4 0

3 years ago

Find the value<br> 9 (2) 7<br> HELPPPP MEEEE I NEED THIS ASAP

ExtremeBDS [4]

Answer:

15/40 which is 3/8

Plug in the numbers into the variables then complete it which then gives you 3/8 simplified

7 0

2 years ago