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3 years ago

Solve for D 6/34 = D/68

1 answer:

3 0

If you would like to solve for the variable in the proportion 6/34 = D/68, you can do this using the following steps:

6/34 = D/68 /*68
D = 6/34 * 68
D = 12

The correct result would be D = 12.

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What is the compound interest if $470 is invested for 9 years at 10% compounded continuously?

disa [49]

Compound interest formula

P = the principal (the initial amount)

r= annual

interest rate (

expressed

as a decimal)

expressed

as a decimal)

annual

interest rate (

expressed

as a decimal)

number of

interest periods

per year

(see the

table below

for more information)

number of years

P is invested

A=amount after t

years

If investment interest rate is

compounded monthly

, then n = 12

If investment interest rate is

compounded quarterly

, then n = 4

If investment interest rate is

compounded semi-annually

, then n = 2

If investment interest rate is

compounded annually

, then n = 1

4 0

3 years ago

What is 2+2? just testing if this works

swat32

The answer is 4.
Yes I think it works nicely, lol
Hope this helps!

7 0

4 years ago

Read 2 more answers

The corner grocery store sells apples for $1.19 per pound. Which store sells apples at a lower unit price than the corner store

Valentin [98]

Answer:

B- 3.48 ÷ 3

Step-by-step explanation:

3.48 ÷ 3= 1.16

Hope this helps

-mercury

4 0

3 years ago

The graph of a cosine function is shown. Which two points on the midline of the function are separated by a distance of one peri

Ray Of Light [21]

Answer: (pi/8, 1) and (5*pi/8, 1)

Step-by-step explanation:

First, the midline is a horizontal line that cuts the graph in two halves.

In this case, we can see that the maximum of the function is y = 2.5, and the minimum is y = -0.5

The difference is:

Diff = (2.5 - (-0.5)) = 3

If we subtract half of the difference (3/2 = 1.5) to the maximum, we get the midline.

Then:

midline: y = 2.5 - (3/2) = 1

the midline is the line y = 1

Now, a period T is such that:

Sin(x) = Sin(x + T)

Two points that are in the midline and that are separated by a period will be two points on the line y = 1, and that are in corresponding parts of the graph.

Here the two points are, counting from left to right, the third and the 11th.

(both of them are in the line y = -1 and in the negative slope part).

The points are:

(pi/8, 1) and (5*pi/8, 1)

6 0

3 years ago

Read 2 more answers

A student claims that 2i is the only imaginary root of a polynomial equation that has real coefficients. Explain the student's m

____ [38]

Answer:

The Fundamental Theorem of Algebra assures that any polynomial f(x)=0 whose degree is n ≥1 has at least one Real or Imaginary root. So by the Theorem we have infinitely solutions, including imaginary roots ≠ 2i

Step-by-step explanation:

1) This claim is mistaken.

2) The Fundamental Theorem of Algebra assures that any polynomial f(x)=0 whose degree is n ≥1 has at least one Real or Imaginary root. So by the Theorem we have infinitely solutions, including imaginary roots ≠ 2i with real coefficients.

$a_{0}x^{n}+a_{1}x^{2}+....a_{1}x+a_{0}$

For example:

3) Every time a polynomial equation, like a quadratic equation which is an univariate polynomial one, has its discriminant following this rule:

$\Delta < 0\\b^{2}-4*a*c$

We'll have n different complex roots, not necessarily 2i.

For example:

Taking 3 polynomial equations with real coefficients, with

$\Delta < 0$

$-4x^2-x-2=0 \Rightarrow S=\left \{ x'=-\frac{1}{8}-i\frac{\sqrt{31}}{8},\:x''=-\frac{1}{8}+i\frac{\sqrt{31}}{8} \right \}\\-x^2-x-8=0 \Rightarrow S=\left\{\quad x'=-\frac{1}{2}-i\frac{\sqrt{31}}{2},\:x''=-\frac{1}{2}+i\frac{\sqrt{31}}{2} \right \}\\x^2-x+30=0\Rightarrow S=\left \{ x'=\frac{1}{2}+i\frac{\sqrt{119}}{2},\:x''=\frac{1}{2}-i\frac{\sqrt{119}}{2} \right \}\\(...)$

2.2) For other Polynomial equations with real coefficients we can see other complex roots ≠ 2i. In this one we have also -2i

$x^5\:-\:x^4\:+\:x^3\:-\:x^2\:-\:12x\:+\:12=0 \Rightarrow S=\left \{ x_{1}=1,\:x_{2}=-\sqrt{3},\:x_{3}=\sqrt{3},\:x_{4}=2i,\:x_{5}=-2i \right \}\\$

4 0

3 years ago