2 years ago

Two walls have the same area. The first wall is in the shape of a square and has a height

Mathematics

1 answer:

STatiana [176]2 years ago

7 0

Answer:

27 feet

Step-by-step explanation:

Two walls have same area

Area of first wall(square) = 18*18 = 324

Area of second wall = 12 * x = 324

324/12 = 27

27 feet

You might be interested in

There were 13 original states. there are now 50 states what fraction of states are the original states

Olenka [21]

The solution is attached as a word file

Download doc

3 0

2 years ago

What is the area, in cm2, of the smallest square that will contain a circle of radius 4 cm?

Georgia [21]

D=2r=2·4=8 cm
A = L² (L=d)
A = 8² = 64 cm²

6 0

3 years ago

What is the volume in cubic centimeters of a rectangular prism that has a length of 6.2 centimeters, a width of 3.5 centimeters,

Rufina [12.5K]

The length is 6.2
the width is 3.5
the height is 10
So the volume =217cm^3

I hope this help

5 0

2 years ago

Read 2 more answers

What is the product? (2x-1)(x+4) 2x²-4 0 2x²+4 0 2x² + 7x-4 2x² – 7x-4

vladimir2022 [97]

Answer:

C) 2x^2+7x-4

Step-by-step explanation:

(2x-1)(x+4)=2x^2-x+8x-4=2x^2+7x-4

3 0

2 years ago

Read 2 more answers

What value of R makes r/ -11 = (-3) true

marissa [1.9K]

Answer:

The value of $r=33$ which makes the equation true.

Step-by-step explanation:

Given the equation

$\frac{r}{-11}=-3$

We have to find the value of r for which the equation must be true.

solving the equation

$\frac{r}{-11}=-3$

Multiply both sides by -11

$\frac{r\left(-11\right)}{-11}=\left(-3\right)\left(-11\right)$

$r=33$

Therefore, the value of $r=33$ which makes the equation true.

VERIFICATION:

Putting $r=33$ in the equation

$\frac{r}{-11}=-3$

$\frac{33}{-11}=-3$

$-3=-3$ ∵ $\frac{33}{-11}=-3$

L.H.S = R.H.S

Therefore, the value of $r=33$ which makes the equation true.

7 0

3 years ago