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sammy [17]
3 years ago
11

Tom took 10 notecards and arranged them in piles of How many piles did Tom make?

Mathematics
1 answer:
mezya [45]3 years ago
6 0

Answer:

If there in piles of 2 you have 2 piles

Step-by-step explanation:

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Mathematics Help Please!!
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3 years ago
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Given that (ax^2 + bx + 3) (x + d) = x^3 + 6x^2 + 11x + 12<br> a + 2b - d = ?
Mariulka [41]

Answer:

Let's solve for a.

(ax2+bx+3)(x+d)=x3+6x2+11x+12a+2b−d

Step 1: Add -12a to both sides.

adx2+ax3+bdx+bx2+3d+3x+−12a=x3+6x2+12a+2b−d+11x+−12a

adx2+ax3+bdx+bx2−12a+3d+3x=x3+6x2+2b−d+11x

Step 2: Add -bdx to both sides.

adx2+ax3+bdx+bx2−12a+3d+3x+−bdx=x3+6x2+2b−d+11x+−bdx

adx2+ax3+bx2−12a+3d+3x=−bdx+x3+6x2+2b−d+11x

Step 3: Add -bx^2 to both sides.

adx2+ax3+bx2−12a+3d+3x+−bx2=−bdx+x3+6x2+2b−d+11x+−bx2

adx2+ax3−12a+3d+3x=−bdx−bx2+x3+6x2+2b−d+11x

Step 4: Add -3d to both sides.

adx2+ax3−12a+3d+3x+−3d=−bdx−bx2+x3+6x2+2b−d+11x+−3d

adx2+ax3−12a+3x=−bdx−bx2+x3+6x2+2b−4d+11x

Step 5: Add -3x to both sides.

adx2+ax3−12a+3x+−3x=−bdx−bx2+x3+6x2+2b−4d+11x+−3x

adx2+ax3−12a=−bdx−bx2+x3+6x2+2b−4d+8x

Step 6: Factor out variable a.

a(dx2+x3−12)=−bdx−bx2+x3+6x2+2b−4d+8x

Step 7: Divide both sides by dx^2+x^3-12.

a(dx2+x3−12)

dx2+x3−12

=

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

a=

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

Answer:

a=

−bdx−bx2+x3+6x2+2b−4d+8x/

dx2+x3−12

Step-by-step explanation:

8 0
3 years ago
Find the value of x (help quick)
o-na [289]

Answer:

c) 3

Step-by-step explanation:

22=2x2 +4

22-4

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18/2

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3 years ago
A person has a bag containing quarters and dimes. There are a total of 61 coins in the bag, and the total value of the coins is
77julia77 [94]

Answer:

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6 0
2 years ago
Find the value of x that makes m || n
ch4aika [34]

Answer:

x=133

Step-by-step explanation:

Given: m║n

This means that 147 and x+14 are <em>alternate exterior angles</em>. This also means that they are equivalent. We can use this information to set up an equation:

x+14=147

Subtract 14 from both sides to isolate x

x=133

8 0
2 years ago
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