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3 years ago

How Much Water Do We Use?

Mathematics

1 answer:

lara31 [8.8K]3 years ago

7 0

Answer:

According to a national study by the Water Research Foundation in 2016, the average shower uses roughly 17 gallons of water and lasts for around eight minutes.

Step-by-step explanation:

it all up in Answer!

You might be interested in

400g of rapberries and 300g of strawberries cost £7.46. 500g of strawberries cost £4.10 work out the cost of 300g of raspberries

MAXImum [283]

Answer: £5.39

Step-by-step explanation:

500g strawberries = 4.10

100 g = 0.82

300g = 2.46

400g raspberries = 7.46 - 2.46 = 5.00

100g = 1.25

300g = 3.75

200g strawberries = 0.82 * 2 = 1.64

3.75 + 1.64 = 5.39

8 0

3 years ago

Please write this out on a piece of paper

horrorfan [7]

///////////////////////

5 0

4 years ago

Read 2 more answers

If a distribution is skewed to the left, which of the following is true of the data set? Select two answers.

solmaris [256]

Answer:

I know (B) is correct, the median is the best measure of center if t distribution is Skewed Left

Step-by-step explanation:

3 0

3 years ago

Use long division to find the quotient below (30x^3+4x^2-150) / (6x-10)

Anni [7]

Answer:

The answer is

A $.5x^2+9x+15$

Step-by-step explanation:

kindly find attached the solving for proper understanding and solution flow.

Given Data

the divisor= $6x-10$

dividend= $30x^3+4x^2-150$

firstly for us to perform the division we need to re write the dividend and include the missing coefficient of x

dividend $=30x^3+4x^2+0x-150$

3 0

4 years ago

In a random sample of 300 attendees of a minor league baseball game, 182 said that they bought food from the concession stand. C

horrorfan [7]

Answer:

90% confidence interval for the proportion of fans who bought food from the concession stand

(0.5603,0.6529)

Step-by-step explanation:

Step(i):-

Given sample size 'n' =300

Given data random sample of 300 attendees of a minor league baseball game, 182 said that they bought food from the concession stand.

Given sample proportion

$p^{-} = \frac{x}{n} = \frac{182}{300} =0.606$

level of significance = 90% or 0.10

Z₀.₁₀ = 1.645

90% confidence interval for the proportion is determined by

$(p^{-} - Z_{0.10}\sqrt{\frac{p(1-p)}{n} } , p^{-} +Z_{0.10}\sqrt{\frac{p(1-p)}{n} })$

$(0.6066 - 1.645\sqrt{\frac{0.6066(1-0.6066)}{300} } ,0.6066+1.645\sqrt{\frac{0.6066(1-0.6066)}{300} })$

(0.6066 - 0.0463 ,0.6066 + 0.0463)

(0.5603,0.6529)

final answer:-

90% confidence interval for the proportion of fans who bought food from the concession stand

(0.5603,0.6529)

5 0

3 years ago