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4 years ago

Becky wrote an expression equivalent to (2.5 + 3)+ 7. which is the expression Becky wrote

Mathematics

1 answer:

Sedaia [141]4 years ago

4 0

Answer:

5.5 + 7

Step-by-step explanation:

Even thought there are no options, I came up with an idea of what she wrote.

(2.5 + 3)+ 7

Solve the expression in the parentheses:

2.5 + 3 = 5.5

So we have:

5.5 + 7

<em>Becky could of written '5.5 + 7'. </em>

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Can't figure out how to set up and check to see if right. 8/11(n-10)=64

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Step-by-step explanation:

$\frac{8}{11}(n-10)=64\\\\\frac{8(x-10)}{11}=64\\ 8(x-10) = 64(11)\\8(x-10) = 704\\8x-80 = 704\\8x= 704+80\\8x=784\\\\\frac{8x}{8}=\frac{784}{8} \\x=98$

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3 years ago

Find the rational zeros of the polynomial function, f(x)= 4x^3-8x^2-19x-7

Dima020 [189]

Answer:

The rational zero of the polynomial are $\pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1$ .

Step-by-step explanation:

Given polynomial as :

f(x) = 4 x³ - 8 x² - 19 x - 7

Now the ration zero can be find as

$\dfrac{\textrm factor of P}{\textrm factor Q}$ ,

where P is the constant term

And Q is the coefficient of the highest polynomial

So, From given polynomial , P = -7 , Q = 4

Now , $\dfrac{\textrm factor of \pm P}{\textrm factor of \pm Q}$

I.e $\dfrac{\textrm factor of \pm P}{\textrm factor of \pm Q}$ = $\frac{\pm 7 , \pm 1}{\pm 4 ,\pm 2,\pm 1 }$

Or, The rational zero are $\pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1$

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subtract 4160 from both sides
x^2+x-4160=0
find the factor (if you want to know how, just ask in the comments)
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so the answer is x could be 64 or -65
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