Answer:
Step-by-step explanation:
In order to write the series using the summation notation, first we need to find the nth term of the sequence formed. The sequence generated by the series is an arithmetic sequence as shown;
4, 8, 12, 16, 20...80
The nth term of an arithmetic sequence is expressed as Tn = a +(n-1)d
a is the first term = 4
d is the common difference = 21-8 = 8-4 = 4
n is the number of terms
On substituting, Tn = 4+(n-1)4
Tn = 4+4n-4
Tn = 4n
The nth term of the series is 4n.
Since the last term is 80, L = 4n
80 = 4n
n = 80/4
n = 20
This shows that the total number of terms in the sequence is 20
According to the series given 4 + 8 + 12 + 16 + 20+ . . . + 80
, we are to take the sum of the first 20terms of the sequence. Using summation notation;
4 + 8 + 12 + 16 + 20+ . . . + 80 =
<span><span><span><span><span>I am so sorry if this is wrong, but
2−5</span>+4</span>+21</span>+1666666</span>−<span>(2)(43)
</span></span><span>=<span><span><span><span>−3+4</span>+21</span>+1666666</span>−<span>(2)(43)
</span></span></span><span>=<span><span>1+21+1666666</span>−<span>(2)(43)
</span></span></span><span>=<span>22+1666666−<span>(2)(43)
</span></span></span><span>=<span>1666688−<span>(2)(43)
</span></span></span><span>=1666688−86
</span><span>Your answer would be 1,666,602
Hope this helps!:)</span>
Answer:
Function 2 is linear
Step-by-step explanation:
It is linear because all of the numbers that in x roc is 1 and y is -4
Answer:
Step-by-step explanation:
Sounds as tho' possible answer choices were listed. Please, share them without being asked to do so. Thank you.
7√(x²) 7√(x²)
------------- = ----------------------
5 √(y³) 5√( y^(3/2) )
We want to get the fractional exponent out of the denominator. To do this, multiply both numerator and denominator by y^(1/2):
7√(x²) 7√(x²) y^(1/2) 7√(x²)·y^(1/2) 7x√y
------------- = --------------------- * ----------- = --------------------- = ----------
5 √(y³) 5√( y^(3/2) ) y^(1/2) 5 √(y²) 5y
This is the final answer. We have succeeded in removing radicals / fractional exponents from the denominator.
Answer:
no inglis sorry Xdxdxd y no se entiende xd
