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1 year ago

HELP PLS NEED THIS ASAP

Mathematics

1 answer:

11Alexandr11 [23.1K]1 year ago

5 0

Answer:

Let x = # of commercials

y = # of movies

<u>System of Equations:</u>

x + y = 90

40x + 110y = 500

Step-by-step explanation:

We have to set our variables before we start solving. After setting the variables, we can set up the equations. If x = # of commercials and y = # of movies, then we can assume x + y = 90, as there have been a total of 90 commercials and movies played altogether. Then, we know that their worth is $500, so the price of all the commercials played and the price of all the movies played (which is 40x + 110y) sum to $500.

(I've just answered this question from your previous post. Unless my answer was wrong, I don't see why you would repost the exact same question.)

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Answer:

a) 0.06 = 6% probability that a person has both type O blood and the Rh- factor.

b) 0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.

Step-by-step explanation:

I am going to solve this question treating these events as Venn probabilities.

I am going to say that:

Event A: Person has type A blood.

Event B: Person has Rh- factor.

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This means that $P(A) = 0.43$

15% of people have Rh- factor

This means that $P(B) = 0.15$

52% of people have type O or Rh- factor.

This means that $P(A \cup B) = 0.52$

a. Find the probability that a person has both type O blood and the Rh- factor.

This is

$P(A \cap B) = P(A) + P(B) - P(A \cup B)$

With what we have

$P(A \cap B) = 0.43 + 0.15 - 0.52 = 0.06$

0.06 = 6% probability that a person has both type O blood and the Rh- factor.

b. Find the probability that a person does NOT have both type O blood and the Rh- factor.

1 - 0.06 = 0.94

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2 years ago

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