All categories

2 years ago

Express 73/5as a decimal.

Mathematics

1 answer:

Assoli18 [71]2 years ago

7 0

Answer:

as a fraction it could be 3/5

Step-by-step explanation:

but as a decimal it would be 0.6

You might be interested in

Ted likes to run long distances. He can run 20 km 95 minutes. He wants to know how many kilometers (k) he will go if he runs at

maxonik [38]

He will run 60km in 285 minutes.

8 0

3 years ago

Read 2 more answers

HELP QUICKLY PLEASE

FromTheMoon [43]

Answer:

should be A

Step-by-step explanation:

Translated left by 7

8 0

3 years ago

Read 2 more answers

In 1911, the temperature in Rapid City,

Sliva [168]

The 3.1 °F/min rate of change of the temperature and 15 minutes change duration gives the change in temperature as 46.5 °F

<h3>How can the change in temperature be found from the rate of change?</h3>

The rate at which the temperature changed = 3.1 °F/min

The duration of the change in temperature = 15 minutes

The relationship between the change in temperature, the rate of change in temperature and the time can be presented as follows;

$3.1 ^{\circ} F/min = \frac{ \delta T }{\delta t} = \frac{ \Delta T }{ \Delta t}$

Where;

∆T = The required change in temperature

∆t = The duration of the change = 15 minutes

Which gives;

∆T = 3.1°F/min × 15 minutes = 46.5 °F

The change in temperature, ∆T = 46.5 °F

Learn more about the rate of change of a variable here:

brainly.com/question/10208814

#SPJ1

8 0

1 year ago

There are two major tests of readiness for college, the act and the sat. act scores are reported on a scale from 1 to 36. the di

ch4aika [34]

Standardized z score for the act result = (30 - 21.5) / 5.4 = 1.574

so for the sat ressult we have 1.574 = (X - 1498) / 316

X = 316 * 1.574 + 1498 = 1995 answer

4 0

3 years ago

Daily high temperatures in St. Louis for the last week were as follows: 95, 92, 93, 92, 95, 90, 90 (yesterday). a) The

hichkok12 [17]

Answer:

a) T = 91.7 degrees

b) T = 90 degrees

c) MAD = 1.9

d) MSE = 5.05

Step-by-step explanation:

Given:

- Daily high temperatures in St. Louis for the last week were as follows:

95, 92, 93, 92, 95, 90, 90

Find:

a) Forecast the high temperature today, using a 3-day moving average.

b) Forecast the high temperature today, using a 2-day moving average.

c) Calculate the mean absolute deviation based on a 2-day moving average, covering all days in which you can have a forecast and an actual temperature.

d) The mean squared error for the 2-day moving average

Solution:

- The set of 3 day moving average is as follows:

4. (95 + 92 + 93) ÷ 3 = 93.33⁰C

5. (92 + 93 + 92) ÷ 3 = 92.33⁰C

6. (93 + 92 + 95) ÷ 3 = 93.33⁰C

7. (92 + 95 + 90) ÷ 3 = 92.33⁰C

8. (95 + 90 + 90) ÷ 3 = 91.667⁰C

- Now use these points on excel sheet to forecast the temperature for today. The line of best fit is given:

T = 91.7 degrees

- The set of 2 day moving average is as follows:

3. (95 + 92) ÷ 2 = 93.5⁰C

4. (95 + 93) ÷ 2 = 92.5⁰C

5. (93 + 92) ÷ 2 = 92.5⁰C

6. (92 + 95) ÷ 2 = 93.5⁰C

7. (95 + 90) ÷ 2 = 92.5⁰C

8. (90 + 90) ÷ 2 = 90⁰C

- Now use these points on excel sheet to forecast the temperature for today. The line of best fit is given:

T = 90 degrees

Error Error^2

3. 93.5⁰C 0.5 0.25

4. 92.5⁰C 0.5 0.25

5. 92.5⁰C 2.5 6.25

6. 93.5⁰C 3.5 12.25

7. 92.5⁰C 2.5 6.25

8. 90⁰C

- The mean absolute deviation as follows:

MAD = Sum of all errors / 5

MAD = (0.5+0.5+2.5+3.5+2.5) / 5

MAD = 1.9

- The mean squared error deviation as follows:

MSE = Sum of all error^2 / 5

MSE = (0.25+0.25+6.25+12.25+6.25) / 5

MSE = 5.05

4 0

3 years ago