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Musya8 [376]
3 years ago
5

Sally agreed a compound interest of 5.5% for a fixed term. If she invested £800 to this agreement, then what was her total at th

e end of 5 years?
Mathematics
1 answer:
Rom4ik [11]3 years ago
3 0

Answer:

£1045.57

Step-by-step explanation:

Using compound interest formula then

A=P(1+i)^{n}

Where A= the future value of the investment/loan, including interest

P = the principal investment amount

r = the annual interest rate

n = the number of times that interest is compounded per unit t

A=800(1+0.055)^{5}\approx 1045.57

Hence her amount t the end of 5 yrs is $1045.57

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Stells [14]

Answer:

y=-4

Step-by-step explanation:

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3 years ago
Please help me with this question
Natali5045456 [20]
Again, In this question too you need to substitute the given variable values into the original expressions. Here, "x" is given as a value of "12" and the variable of "y" is given as as value of "2". A single variable of "x" in the numerator is given in the expression. On the denominator the variable of "y" with a value of "2" is multiplied by a numbered value of "3". So, now showing this by the help of LaTeX.

\mathbf{Since, \: x = 12, \: y = 2}

\mathbf{\therefore \quad \dfrac{12}{3 \times 2}}

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Hope it helps.
3 0
3 years ago
Give this problem a try and try to solve this​
tia_tia [17]

Answer:

No solution

Step-by-step explanation:

Given equation is,

\frac{x^{\frac{1}{2}}+x^{-\frac{1}{2}}}{1-x}+\frac{1-x^{-\frac{1}{2}}}{1+x^\frac{1}{2}}-\frac{(4+x)^\frac{1}{2}}{(1-x)^\frac{1}{2}}=0

\frac{x^{\frac{1}{2}}+x^{-\frac{1}{2}}}{1-x}+\frac{1-x^{-\frac{1}{2}}}{1+x^\frac{1}{2}}=\frac{(4+x)^\frac{1}{2}}{(1-x)^\frac{1}{2}}

\frac{(x+1)}{\sqrt{x}(1-x)}+\frac{(\sqrt{x}-1)}{\sqrt{x}(1+\sqrt{x})}=(\frac{4+x}{1-x})^{\frac{1}{2}}

\frac{(\sqrt{x}+1)(x+1)+(\sqrt{x}-1)(1-x)}{\sqrt{x}(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^{\frac{1}{2}}

\frac{x\sqrt{x}+x+\sqrt{x}+1+\sqrt{x}-1-x\sqrt{x}+x}{\sqrt{x}(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^\frac{1}{2}

\frac{2x+2\sqrt{x}}{\sqrt{x}(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^\frac{1}{2}

\frac{2(\sqrt{x}+1)}{(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^\frac{1}{2}

\frac{2}{1-x}=(\frac{4+x}{1-x})^\frac{1}{2}  if x ≠ ±1

(\frac{2}{1-x})^2=\frac{4+x}{1-x}  [Squaring on both the sides of the equation]

\frac{4}{(1-x)}=(4+x)

4 = (1 - x)(4 + x)

4 = 4 - 4x + x - x²

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x(x + 3) = 0

x = 0, -3

But both the solutions x = 0 and x = -3 are extraneous solutions, given equation has no solution.

5 0
4 years ago
Read 2 more answers
Identify the mistake:
Andrews [41]
Should have subtracted 3x
4 0
3 years ago
Read 2 more answers
Find x, y and z for the following triangle. ​<br>Please show the steps with details, Thanks!
Lubov Fominskaja [6]

Answer:

x = 100°

y = 125°

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Step-by-step explanation:

A straight line is 180°

A triangle is 180°

Solve in this order:

X: 180 - 80 = 100

Z: 180 - 80 - 45 = 55

Y: 180 - 55 = 125

5 0
3 years ago
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