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MA_775_DIABLO [31]
2 years ago
9

Select proportional or not proportional to correctly classify the pair of ratios. 1.2/3 and 1.8/4.5

Mathematics
2 answers:
satela [25.4K]2 years ago
8 0

Answer:Proportional

Step-by-step explanation:

Gnesinka [82]2 years ago
6 0

Answer:

Proportional.

Step-by-step explanation:

Find the cross products. If they are same, then they are proportional.

\dfrac{1.2}{3} = \dfrac{1.8}{4.5}

Cross multiply,

1.2 * 4 .5       =         3*1.8

      5.40      = 5.4

So, they are proportional.

Or

Multiply the numerator and denominator of 1.2/3 by 1.5

\dfrac{1.2*1.5}{3*1.5}=\dfrac{1.8}{4.5}

From this we come to know they are proportional

Or

1.2 : 3 :: 1.8 : 4.5

Product of means = 3*1.8 = 5.4

Product of extremes = 1.2*4.5 = 5.4

Product of means = product of extremes. So, they are proportional.

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What is the midpoint between points 1,4 and 9,16​
kondaur [170]

Answer:

(5,10)

Step-by-step explanation:

Midpoint = (x1+x2)/2 , (y1+y2)/2

3 0
3 years ago
Rewrite the expression −7/8 − 2 1/4 ​as the sum of two numbers.
pychu [463]

Answer:

-3 1/8.

Step-by-step explanation:

−7/8 − 2 1/4

= -7/8 + -9/4

= -7/8 - 18/8

= -25/8

= -3 1/8.

4 0
3 years ago
Solve the equation for all real values of x.<br> cosxtanx - 2 cos x=-1
IceJOKER [234]

Solution to equationcosxtanx - 2 cos^2 x=-1 for all real values of x is  x=2k\pi + \frac{\pi}{6}  , x=2k\pi + \frac{5\pi}{6} .

<u>Step-by-step explanation:</u>

Here we have , cosxtanx - 2 cos^2 x=-1. Let's solve :

⇒  cosxtanx - 2 cos^2 x=-1

⇒  cosx(\frac{sinx}{cosx}) - 2 cos^2 x=-1

⇒  sinx = 2 cos^2 x-1

⇒  sinx = 2 (1-sin^2x)-1

⇒  sinx = 1-2sin^2x

⇒  2sin^2x+sinx-1=0

By quadratic formula :

⇒ sinx = \frac{-b \pm \sqrt{b^2-4ac} }{2a}

⇒ sinx = \frac{-1 \pm \sqrt{1^2-4(2)(-1)} }{2(2)}

⇒ sinx = \frac{-1 \pm3}{4}

⇒ sinx = \frac{1}{2} , sinx =-1

⇒ sinx = sin\frac{\pi}{6} , sinx = sin\frac{3\pi}{2}

⇒ x=\frac{\pi}{6} , x=\frac{3\pi}{2}

But at x=\frac{3\pi}{2} we have equation undefined as cos\frac{3\pi}{2}=0 . Hence only solution is :

⇒ x=\frac{\pi}{6}

Since , sin(\pi -x)=sinx

⇒ x=\pi -\frac{\pi}{6} = \frac{5\pi}{6}

Now , General Solution is given by :

⇒ x=2k\pi + \frac{\pi}{6}  , x=2k\pi + \frac{5\pi}{6}

Therefore , Solution to equationcosxtanx - 2 cos^2 x=-1 for all real values of x is  x=2k\pi + \frac{\pi}{6}  , x=2k\pi + \frac{5\pi}{6} .

3 0
3 years ago
Simplify the equation -4d - 37 = 7d + 18
exis [7]

Answer:

d=-5

Step-by-step explanation:

-4d-37=7d +18

move the terms to its correct side

-4d-7d=18+37

calculate the like terms together.

-11d=55

divide both sides by -11. both of the negavtive (-11) will cancel out and become d on the left and on the right 55 will be divided by -11 = -5. the 5 is negative because there's a negative -11 if there were a postive 11 it will be 5 instead of D=-5

5 0
3 years ago
Read 2 more answers
Determine the vertex of the quadratic function.
const2013 [10]

Answer:

B

Step-by-step explanation:

The vertex is the turning point of the quadratic function.

In this case it lies on the x- axis at (2, 0 ) → B

6 0
3 years ago
Read 2 more answers
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