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wlad13 [49]
2 years ago
13

A factory produces weighted balls to use for exercise by filling spherical rubber shells of different sizes with the sand like m

aterial. The materials density is 1.5 grams per centimeter. Assuming the shell weighs 10 grams, what should the balls radius so, when full, it weighs 1 kilogram(or 1000 grams)?
Mathematics
2 answers:
anzhelika [568]2 years ago
8 0

Answer:

r=5.4

As mentioned above, the actual \goldE{\text{total quantity}}total quantitystart color #a75a05, start text, t, o, t, a, l, space, q, u, a, n, t, i, t, y, end text, end color #a75a05 is 1000-10=\goldE{990}1000−10=9901000, minus, 10, equals, start color #a75a05, 990, end color #a75a05 grams, since we are trying to find the volume of the air within the shell.

Let's denote the ball's radius as rrr. Then, the \maroonD{\text{volume}}volumestart color #ca337c, start text, v, o, l, u, m, e, end text, end color #ca337c is \maroonD{\dfrac43\pi r^3}  

3

4

​  

πr  

3

start color #ca337c, start fraction, 4, divided by, 3, end fraction, pi, r, cubed, end color #ca337c.

Now we can plug \blueE{\text{density}=1.5}density=1.5start color #0c7f99, start text, d, e, n, s, i, t, y, end text, equals, 1, point, 5, end color #0c7f99, \goldE{\text{total quantity}=990}total quantity=990start color #a75a05, start text, t, o, t, a, l, space, q, u, a, n, t, i, t, y, end text, equals, 990, end color #a75a05, and \maroonD{\text{volume}=\dfrac43\pi r^3}volume=  

3

4

​  

πr  

3

start color #ca337c, start text, v, o, l, u, m, e, end text, equals, start fraction, 4, divided by, 3, end fraction, pi, r, cubed, end color #ca337c in the equation.

nataly862011 [7]2 years ago
6 0

Answer:

5.4

Step-by-step explanation:

Khan-Academy, correct

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Tju [1.3M]
Not necessarily. \mathbf u and \mathbf v may be linearly dependent, so that their span forms a subspace of \mathbb R^2 that does not contain every vector in \mathbb R^2.

For example, we could have \mathbf u=(0,1) and \mathbf v=(0,-1). Any vector \mathbf w of the form (r,0), where r\neq0, is impossible to obtain as a linear combination of these \mathbf u and \mathbf v, since

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8 0
3 years ago
Nth term to 4 1 -2 -5 -8
AURORKA [14]

4

4 - 3 = 1

1 - 3 = -2

-2 - 3 = -5

-5 - 3 = -8

It's the arithmetic sequence.

a_n=a_1+(n-1)d

a_1=4,\ d=-3

substitute

a_n=4+(n-1)(-3)=4-3n+3=-3n+7

Answer: a_n=-3n+7


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3 years ago
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5 0
2 years ago
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A) Dati cinci exemple de numere intregi mai mici ca zero.​
12345 [234]

Answer:

Numerele întregi pozitive sunt toate numerele întregi mai mari decât zero: 1, 2, 3, 4, 5, .... Numere întregi negative sunt toate opusele acestor numere întregi: -1, -2, -3, -4, -5, .... Nu considerăm că zero este un număr pozitiv sau negativ. Pentru fiecare număr întreg pozitiv, există un număr întreg negativ, iar acești numere întregi se numesc opuse. De exemplu, -3 este opusul lui 3, -21 este opusul lui 21 și 8 este opusul lui -8. Dacă un număr întreg este mai mare decât zero, spunem că semnul său este pozitiv. Dacă un număr întreg este mai mic decât zero, spunem că semnul său este negativ.

Step-by-step explanation:

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2 years ago
If C(5,-5) and D(7,3), then what is the length of CD?​
Aleks04 [339]

Answer:

≈ 6.16

Step-by-step explanation:

Calculate the distance (d) using the distance formula

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with (x₁, y₁ ) = C(5, - 5) and (x₂, y₂ ) = D(7, 3)

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