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2 years ago

Here is an expression: 2 + 3t

Mathematics

2 answers:

erastova [34]2 years ago

5 0

Step-by-step explanation

2 + 12 = 14

Dima020 [189]2 years ago

3 0

2+3t
When t is 1
2+3(1)
2+3
5

When t is 4
2+3(4)
2+12
14

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alberto knows that all the lines and rays are congruent to each other . he reasons that all segments must therefore be congruent

saw5 [17]

Answer:

Step-by-step explanation:

Alberto is correct in reasoning that all lines and rays are congruent to each other but incorrect in his reasoning about the line segments.

Line segments are equal in measure only when they are equal in length. They can have any orientation on a plane.

Since, AB = 3 units

CD = 4 units

Therefore, AB ≠ CD

Error in AB ≅ CD

7 0

2 years ago

Factor the four term polynomial by grouping.<br>10x^3-15x^2+6x-9

goldfiish [28.3K]

Answer:

(5x² + 3) (2x-3)

Step-by-step explanation:

10x³ - 15x² + 6x - 9 (rearrange)

10x³+ 6x - 15x² - 9 (group using parentheses)

(10x³+ 6x) - (15x² + 9) (factor out 2x from first term and 3 from second term)

2x (5x²+ 3) - 3(5x² + 3) (factor out (5x²+3) )

(5x² + 3) (2x-3) (answer)

5 0

3 years ago

Expressions that simplify to the same expression are called ____ expressions.

larisa86 [58]

They're called equivalent expressions

5 0

2 years ago

Read 2 more answers

the village was polyglot. if the ratio of bilingual denizens to trilingual denizens was 14 to 3 and the denizens totaled 3400 ho

Travka [436]

Bilingual : trilingual = 14 : 3

So, ...
trilingual : total = 3 : (14+3) = 3 : 17

The number of trilingual denizens was (3/17)*3400 = 600.

7 0

2 years ago

Use the given information to find the exact value of the trigonometric function

eimsori [14]

$\begin{gathered} \csc \theta=-\frac{6}{5} \\ \tan \theta>0 \\ \cos \frac{\theta}{2}=\text{?} \end{gathered}$

Half Angle Formula

$\cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}}$ $\tan \theta>0\text{ and csc}\theta\text{ is negative in the third quadrant}$ $\begin{gathered} \csc \theta=-\frac{6}{5}=\frac{r}{y} \\ x^2+y^2=r^2 \\ x=\pm\sqrt[\square]{r^2-y^2} \\ x=\pm\sqrt[\square]{6^2-(-5)^2} \\ x=\pm\sqrt[\square]{36-25} \\ x=\pm\sqrt[\square]{11} \\ \text{x is negative since the angle is on the 3rd quadrant} \end{gathered}$ $\begin{gathered} \cos \theta=\frac{x}{r}=\frac{-\sqrt[\square]{11}}{6} \\ \cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}} \\ \cos \frac{\theta}{2}is\text{ also negative in the 3rd quadrant} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{1+\frac{-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{\frac{6-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}} \\ \\ \end{gathered}$

Answer:

$\cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}$

Checking:

$\begin{gathered} \frac{\theta}{2}=\cos ^{-1}(-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}) \\ \frac{\theta}{2}=118.22^{\circ} \\ \theta=236.44^{\circ}\text{ (3rd quadrant)} \end{gathered}$

Also,

$\csc \theta=\frac{1}{\sin\theta}=\frac{1}{\sin (236.44)}=-\frac{6}{5}\text{ QED}$

The answer is none of the choices

7 0

6 months ago