Yes. Changing the the word problem into a function, you get 30x=y.
30 = Fixed Length
x = width
y = area
No matter what width (x) you choose, the area (y) is going to be a multiple of 30 (the fixed length) because with two numbers being multiplied, if there is a fixed number that will always be the multiple and not the multiplier. For example, 10 multiplied by every number 1-10 is going to be a multiple of 10.
10x1=10, 10x2=20, 10x3=30, etc
So if Tom chooses any of these widths (x) 5, 10, or 15, y (the area) will be a multiple of 30.
30(5)=150
30(10)=300
30(15)=450
So as we double 5 to get 10, our outcome is doubled 150 to 300 and so forth. Hope this helps.
Answer:
parte 1) | Superprof
1 Indica cuáles de las siguientes expresiones son monomios. En caso de ... 4 Encuentra el valor numérico del polinomio P(x) = x^3 + 3x^2 - 4x - 12 ... d) (10x – 5/4x³ + 5/2x² – 1/2) : (5x)
10% of of $48 is an additional discount of $4.80.
Rocco's friend will have to pay $43.20 for the putter.
Answer:
Domain and range: [0, ∞)
Step-by-step explanation:
There is no limit to the number of concert tickets someone can buy, but there cannot be negative concert tickets. The domain, or what the input can be, is [0, ∞) as it can be greater than or equal to 0
The range is the total cost, or what the output can be. Since the total cost is the number of tickets multiplied by 55 (as it is $55 per ticket), this can be represented by 55 * number of tickets. The total cost cannot be negative, but it can be 0 if no one buys tickets. As there is no limit to the amount of tickets someone can buy, there is no limit to what the total cost could be, making the range [0, ∞)
Always eliminate the first one before moving on. Remember to drop down monomials, like you would a normal division problem.
2x² + 10x + 18
__________________
x + 3 | 2x³ + 16x² - 12x + 9
-(2x³ + 6x²)
-------------------------------
10x² - 12x
-(10x² - 30x)
-----------------------------
+ 18x + 9
- (18x + 54)
----------------------
-45
2x² + 10x + 18 R: -45/x + 3 is your answer R: = remainder
hope this helps
