Answer:
1) B
2) C
3) B
Step-by-step explanation:
Radius = D/2 = 7/2 × 2 = 7/4
Circumference = pi × D
= 7/2 pi
7/2 × 3.14 = 10.99
Approximately 11
-3x+7<11
-3x<4
x>-4/3
So anything less than or equal to -4/3 does not belong to the solution set.
With your update:
"<span>The options is 4,-1,-5,and 0"
-5 does not belong to the solution set...</span>
Answer:
Let y(x)="x is valid and x has true premises" and z(x)="x has a true conclusion".
Step-by-step explanation:
The universe U is the collection of all arguments so that x∈U. The statement uses the universal quantifier ∀ represented by the word "Every". The words "valid", "with true premises" and "has a true conclusions" are properties of an argument x.
We can interptet the statement as: "For all x, (x is valid and x has true premises)→(x has a true conclusion)". Symbolically, (∀x)(y(x)→z(x)). The implication → can be read as "if y(x) then z(x)".
Answer:
Step-by-step explanation:
Given
Required
Determine the difference
Represent this with d.
d is calculated using
The equation becomes
I’m pretty sure a is always and b is sometimes.
