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RideAnS [48]
3 years ago
12

Help me please!! This test is due tomorrow!! What's the answer? 5 stars and brainliest!

Mathematics
1 answer:
puteri [66]3 years ago
3 0

Answer:

5/36

Step-by-step explanation:

I added them up

Tell me if I am wrong.

Can I get brainliest

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Diego has 200 students in his grade which is 2 times as many as Lin. Lin’s grade has x students. Write this equation.
Gnoma [55]
200 divided by 2 = x

Hope this helps!
6 0
3 years ago
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What is 1 3/4 + 1/8<br> I rly need help tjxs
Andru [333]
The answer is 1 and 7/8, all you have to do is turn the 3/4 into eighths.
8 0
4 years ago
Which row of the input/output table is incorrect?
zaharov [31]

Row A:   x = 3

y = 2x - 3

y = 2(3) - 3 = 3      This is correct

Row B: x = 5

y = 2x - 3

y = 2(5) - 3 = 7        This is correct

Row C: x = 7

y = 2x - 3

y = 2(7) - 3 = 11      this is correct

Row D: x = 10

y = 2x - 3

y = 2(10) - 3 = 17  THIS IS INCORRECT, SO ROW D

8 0
3 years ago
Find the measure of y. Polygon Angle-Sum theorems
Alchen [17]

Answer:

z = 70°

y = 103°

Step-by-step explanation:

From the picture attached,

110° + z° = 180° [Supplementary angles]

z = 180 - 110

z = 70°

Since sum of interior angles of a polygon = (n - 2)×180°

where n = number of sides of the polygon

For a quadrilateral (n = 4),

Sum of interior angles = (4 - 2) × 180°

                                     = 360°

z° + y° + 100° + 87° = 360°

70° + y° + 187° = 360°

y = 103°

Therefore, measure of the angles x = 70° and y = 103°.

8 0
3 years ago
At noon, ship A is 130 km west of ship B. Ship A is sailing east at 25 km/h and ship B is sailing north at 20 km/h. How fast is
Hitman42 [59]

Answer:

answer = 12.87 km/h

Step-by-step explanation:

Given

Ship A is sailing east at 25 km/h = \frac{dx}{dt}

ship B is sailing north at 20 km/h =\frac{dy}{dt}

here x and y are the  sailing at t = 4 : 00 pm for ship A and B respectively

so we get x = 4 ×25 =100 km/h

                 y = 4× 20 = 80 km/h

let z is the distance between the ships, we need to find \frac{dz}{dt} at t = 4 hr

At noon, ship A is 130 km west of ship B (12:00 pm)

so equation will be

z^2 = (130-x)^2 + y^2......................(i)\\put x = 100 and y = 80 \\\\we |  | get \\

z^2 = 30^2 + 80^2\\z =\sqrt{7300} km/h

derivative first equation w . r. to t we get

2z\frac{dz}{dt} =-2(130-x)\frac{dx}{dt}+2y\frac{dy}{dt}

\frac{dz}{dt} =\frac{1}{z}[(x -130)\frac{dx}{dt} +y\frac{dy}{dt}]

\frac{dz}{dt} = \frac{( -20\times25 + 80\times20)}{\sqrt{7300} }

     = \frac{1100}{85.44}\\  = 12.87km/h

8 0
3 years ago
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