Answer:
See Explanation
Step-by-step explanation:
According to the Question,
Steps of construction:
- Step I - Draw a line segment AB = 7 cm with the help ruler.
- Step II - with vertex A, by using compass take more than half of AB and draw arcs, one on each side of AB.
- Step III - with vertex B, by using a compass with the same length, cut the previous arcs at X and Y respectively.
- Step IV - with help of the ruler join the points X and Y Thus XY is the perpendicular bisector of line AB.
(For Diagram please find in attachment)
Answer:
A
Step-by-step explanation:
Given
y - 2x - 8 = 0 ( add 2x + 8 to both sides )
y = 2x + 8 → (1)
y² + 8x = 0 → (2)
Substitute y = 2x + 8 into (2)
(2x + 8)² + 8x = 0 ← expand left side using FOIL and simplify
4x² + 32x + 64 + 8x = 0
4x² + 40x + 64 = 0 ( divide through by 4 )
x² + 10x + 16 = 0 ← in standard form
(x + 8)(x + 2) = 0 ← in factored form
x + 8 = 0 ⇒ x = - 8
x + 2 = 0 ⇒ x = - 2
Substitute these values into (1) for corresponding values of y
x = - 8 : y = 2(- 8) + 8 = - 16 + 8 = - 8 ⇒ P (- 8, - 8)
x = - 2 : y = 2(- 2) + 8 = - 4 + 8 = 4 ⇒ Q (- 2, 4 )
Calculate the length of PQ using the distance formula
PQ = 
with (x₁, y₁ ) = P (- 8, - 8) and (x₂, y₂ ) = Q (- 2, 4 )
PQ = 
= 
= 
= 
= 
= 
=
× 
= 6
→ A
Answer:
Number of sent mail = 36
Number of received mail = 75
Step-by-step explanation:
Let,
x be the number of mails sent
y be the number of mails received
According to given statement;
x + y = 111 Eqn 1
y = 2x + 3 Eqn 2
Putting value of y from Eqn 2 in Eqn 1
x + 2x + 3 = 111
3x = 111 - 3
3x = 108
Dividing both sides by 3

Putting x = 36 in Eqn 2
y = 2(36) + 3
y = 72 + 3 = 75
Hence,
Number of sent mail = 36
Number of received mail = 75