Answer:Ok, we have:
d(t) = 3*t^2 + 5*t - 2.
The first interval is:
(2, 3)
and remember that, for an interval (a,b), the difference quotient is:
D = (f(b) - f(a))/(b -a)
Then in this first interval we have:
So the average rate of change in (2,3) is 20.
now, in (2, 2.5) we have:
So here the rate of change is 9.25
And in the interval (2, 2.1) we have:
So in this interval the rate of change is 1.73
Step-by-step explanation: hope this helps luvv
