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3 years ago

Can you help me .....................?

Mathematics

1 answer:

aniked [119]3 years ago

5 0

Answer:

11/18

Step-by-step explanation:

The desired probability is the sum of ...

... (probability of choosing a coin) × (p(heads) on that coin)

Since the coins are chosen at random, we assume the probability of choosing a given coin is 1/3. Then ...

... p(heads) = (1/3)·(1/2) + (1/3)·1 + (1/3)·(1/3) = 1/6 + 1/3 + 1/9 = (3 +6 + 2)/18

... p(heads) = 11/18

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Find the equation of a line that contains the points (6,3) and (6,−2).

RSB [31]

Answer:

x = 6

Step-by-step explanation:

First find the gradient,

$Gradient = \frac{y2-y1}{x2-x1} = \frac{-2-3}{6-6} =\frac{-5}{0} =0$

Since this line has no gradient, it means that it's a horizontal or vertical line. We cannot substitute in the values because the gradient is 0 so this line will only be x = 6

3 0

3 years ago

Read 2 more answers

PLEASE HELP 70 POINTS

AlexFokin [52]

Answer:

-1 = -5

0 = -1

2 = 5

Step-by-step explanation:

In order to do this you need to follow these five (5) steps:

1) Know what each of the variables mean in an equation of a line. The equation of a line is y = mx + b where y = y-coordinate, m = slope, x = x-coordinate, and b = y-intercept. (Remember that the slope is the steepness of a line and the y-intercept is the point where the line intersects the y-axis. The x- and y-coordinates are values of the points on the line of y = 3x - 1.)

2) Identify the m (slope) and the b (y-intercept). The slope is 3, which can also be written as 3/1. The y-intercept is -1. (Remember that subtraction of 1 is the SAME thing as adding -1!) Since the y-intercept is a point it will be plotted at (0, -1).

3) Plot the y-intercept first. Start at the origin (intersection of the x- and y-axes) since the x coordinate is 0. Then move DOWN 1 unit since the y-coordinate is negative.

4) Use the m (slope) to plot at least three new points. The slope can also be represented as "rise/run" or the amount of units that you move UP or DOWN (vertically), then LEFT or RIGHT (horizontally). (Remember: if the numerator is positive (move UP); numerator is negative (move DOWN); denominator is POSITIVE (move RIGHT); denominator is NEGATIVE (move LEFT)). Since our slope is 3/1, and both the numerator and denominator are POSITIVE, that means we will be "rising" (moving UP) 3 units and "running" (moving RIGHT) 1 unit.

Start at the y-intercept of (0, -1) and move up 3 units and to the right 1 unit. You should be at (1, 2). Plot a point here. Then do it again. You should now be at (2, 5). Plot another point. Now, do it one more time. You should now be at (3, 8). Plot your last point. (If you wish to continue plotting additional points, feel free to do so.)

4 0

3 years ago

Read 2 more answers

NEED HELP ASAP 20POINTS The energy (and cost) needed to operate an air conditioner is proportional to the volume of a space that

insens350 [35]

Answer:

The daily cost of cooling the large warehouse with the same model of air conditioner is $\$1,953$

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube

In this problem

The scale factor is equal to 2.5

The scale factor elevated to the cube is $2.5^{3} =15.625$

To estimate the daily cost of cooling the large warehouse with the same model of air conditioner, multiply $125.00 by the scale factor elevated to the cube

$\$125(15.625)=\$1,953$

4 0

3 years ago

If the lengths of two sides of a triangle are 5 and 9, respectively, which of the following could be the length of the third sid

slamgirl [31]

There are two answers:

B) 5

C) 8

==============================================

Explanation:

If we had a triangle with sides a, b and c, then we can say

b-a < c < b+a

where b is larger than 'a'. This is the triangle inequality theorem

In this case, a = 5 and b = 9 so,

b-a < c < b+a

9-5 < c < 9+5

4 < c < 14

Telling us that c is some number between 4 and 14, not including either endpoint. If c is a whole number, then c could be any value from this set: {5,6,7,8,9,10,11,12,13}

We see that the numbers 5 and 8 are in this set. The values 3 and 15 are not in the set.

3 0

3 years ago

Two problems here I need solved! I need every step, so please have that with your answers!!

Free_Kalibri [48]

QUESTION 1

We want to solve,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-6x+8}$

We factor the denominator of the fraction on the right hand side to get,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-4x - 2x+8}.$

This implies
$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x(x-4) - 2(x - 4)}.$

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{(x-4)(x - 2)}$

We multiply through by LCM of
$(x-4)(x - 2)$

$(x - 2) + x(x-4) = 2$

We expand to get,

$x - 2 + {x}^{2} - 4x= 2$

We group like terms and equate everything to zero,

${x}^{2} + x - 4x - 2 - 2 = 0$

We split the middle term,

${x}^{2} + - 3x - 4 = 0$

We factor to get,

${x}^{2} + x - 4x- 4 = 0$

$x(x + 1) - 4(x + 1) = 0$

$(x + 1)(x - 4) = 0$

$x + 1 = 0 \: or \: x - 4 = 0$

$x = - 1 \: or \: x = 4$

But
$x = 4$
is not in the domain of the given equation.

It is an extraneous solution.

$\therefore \: x = - 1$
is the only solution.

QUESTION 2

$\sqrt{x+11} -x=-1$

We add x to both sides,

$\sqrt{x+11} =x-1$

We square both sides,

$x + 11 = (x - 1)^{2}$

We expand to get,

$x + 11 = {x}^{2} - 2x + 1$

This implies,

${x}^{2} - 3x - 10 = 0$

We solve this quadratic equation by factorization,

${x}^{2} - 5x + 2x - 10 = 0$

$x(x - 5) + 2(x - 5) = 0$

$(x + 2)(x - 5) = 0$

$x + 2 = 0 \: or \: x - 5 = 0$

$x = - 2 \: or \: x = 5$

But
$x = - 2$
is an extraneous solution

$\therefore \: x = 5$

7 0

4 years ago