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katovenus [111]
4 years ago
13

The activity of tocopherols is destroyed by

Chemistry
1 answer:
grandymaker [24]4 years ago
3 0
<span>A. Commercial cooking
</span>
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Answer

to do homework or not

Explanation:

you can figure it out in one second

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A piece of aluminum has a volume of 12 cm3and a mass of 32 g. What is its density? Do not forget the units.
Contact [7]

Answer:

<h3>The answer is 2.67 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass of metal = 32 g

volume = 12 cm³

The density is

density =  \frac{32}{12}  =  \frac{8}{3}  \\  = 2.6666666...

We have the final answer as

<h3>2.67 g/cm³</h3>

Hope this helps you

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Which of these sources is most likely to be credible when it comes to information on the advantages and disadvantages of using p
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How many ammonium ions and how many sulfate ions are present in a 0.310 mol sample of nh42so4?
Rudik [331]

1.87* 10^{23} sulphate ions and 1.87* 10^{24} ammonium ions are present in a 0.310 mole sample of  (NH₄)₂SO₄ .

<h3>What is a mole?</h3>

The International System of Units uses the mole (symbol: mol) as the unit of material quantity (SI). How many elementary entities of a particular substance are present in an object or sample is determined by the quantity of that material.

There are precisely 6.022140761023 elementary entities in a mole. An elementary entity can be an atom, a molecule, an ion, an ion pair, or a subatomic particle like an electron depending on what the substance is.

How this is calculated?

  • The subscripts next to each atom allow you to find the number of moles of each element in the compound.
  • Then, in every mole of (NH₄)₂SO₄ there are:

2 moles of ammonium (NH₄) ions and 1 mole of sulfate (SO₄) ions.

  • Number of sulphate ions:
  • 0.310 moles of( NH_{4})_{2} SO_{4} *\frac{ 1 sulphte mole}{1mole of( NH_{4})_{2}SO_{4} }*\frac{6.023*10^{23}}{ 1 sulphte  mole}  =1.87*10^{23}
  • Number of ammonium ions:

   0.310 moles of( NH_{4})_{2} SO_{4} *\frac{ 10 ammonium mole}{1mole of( NH_{4})_{2}SO_{4} }*\frac{6.023*10^{23}}{ 1 ammonium mole}  =1.87*10^{24}

To know more about moles, refer:

brainly.com/question/19964502

#SPJ4

3 0
2 years ago
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