We can use the ideal gas law equation to find the pressure
PV = nRTwhere
P - pressure
V - volume - 2.6 x 10⁻³ m³
n - number of moles - 0.44 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 25 °C + 273 = 298 K
substituting the values into the equation,
P x 2.6 x 10⁻³ m³ = 0.44 mol x 8.314 Jmol⁻¹K⁻¹ x 298 K
P = 419 281.41 Pa
101 325 Pa is equivalent to 1 atm
Therefore 419 281.41 Pa - 1/ 101 325 x 419 281.41 = 4.13 atm
Pressure is 4.13 atm
Answer:
m=dxv
= 10.5 x 965 = 10132.5 rounded off to 10100 g
Explanation:
Answer:
They have to all have to do with the movement/transfer of heat.
Answer:
The answer to your question is: 0.1 M
Explanation:
data
Volume of AgNO3 = 20.00 ml
1000 ml -------------- 1 l
20 ml --------------- x
x = 20x 1 /1000 = 0.02
AgCl = 0.2867 g
MW of AgCl = 35.45 + 107.9 = 143.35 g
143.35 g -------------- 1 mol
0.2867 g ------------- x
x = 0.2867 x 1 / 143.35 = 0.002 moles of AgCl
From the balance reaction we see that the proportion of AgNO3 to AgCl is 1:1, then
1 mol of AgNO3 -------------------- 1 mol of AgCL
x --------------------- 0.002 moles of AgCl
x = 0.002 moles of AgNO3
This moles of AgNO3 are in 20 ml or 0.02 liters
So, Molarity = # moles/liter
Molarity = 0.002 moles/ 0.02 = 0.1 M
