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Bingel [31]
3 years ago
13

A sample compound contains 9.11 g Ni and 5.89g F. What is the empirical formula of this compound?

Chemistry
2 answers:
Alexxx [7]3 years ago
8 0

The empirical formula of the compound is C. NiF₂.

<em>Step 1</em>. Calculate the <em>moles of each element</em>

The empirical formula is the simplest whole-number ratio of atoms in a compound.

The ratio of atoms is the same as the ratio of moles.

So, our job is to calculate the molar ratio of Ni to F.

Moles of Ni = 9.11 g Ni × (1 mol Ni /(58.69 g Ni) = 0.1552 mol Ni

Moles of F = 5.89 g F × (1 mol F/19.00 g F) = 0.3100 mol F

<em>Step 2</em>. Calculate the <em>molar ratio</em> of the elements

Divide each number by the smallest number of moles

Ni:F = 0.1552:0.3100 = 1:1.997 ≈ 1:2

<em>Step 3</em>: Write the <em>empirical formula</em>

EF = NiF₂

Novay_Z [31]3 years ago
3 0

Answer:

C

Explanation:

Edg2020

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3 years ago
If 1.3 L of C3H8 combusts according to the equation below, how much CO2 will be produced?
SCORPION-xisa [38]

Answer:

0.162 moles of CO₂ are produced by this reaction

Explanation:

The reaction is:

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As we have the volume of propane, we need to know the mass that has reacted, so we apply density's concept.

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6 0
3 years ago
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D. potential

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5 0
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Rasek [7]

Answer:

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Explanation:

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Functional group like -OH is usually found in Alcohol . Due to the presence of this functional group (-OH) alcohol possess a peculiar chemical properties. The compounds possess an hydrogen bond which invariably lead to the higher boiling points of the alcohol compounds.  Other functional group can be bonds like double bond found in alkene compound or triple  bond found in alkyne compound.

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