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3 years ago

A bag contains A markers, 3/8 of which are red. How many other color markers are in the bag?

2 answers:

6 0

8 is the total number of markers in the bag. There are 3 out of 8 that are red. 8-3=5 so there are 5 out of 8 markers that are not red and that are other colors - or 5/8 are other colors.

Crank3 years ago

3 0

Answer:

$\frac{5A}{8}$ are the other color markers in the bag.

Step-by-step explanation:

A bag contains A markers, $\frac{3}{8}$ of which are red.

Number of red markers = $\frac{3}{8}$ of A

= $\frac{3A}{8}$

Now number of other color markers in the bag = Total markers - number of red markers

Number of other markers = A - $\frac{3A}{8}$

= $\frac{8A-3A}{8}$

= $\frac{5A}{8}$

therefore, $\frac{5A}{8}$ are the other color markers in the bag.

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central angle of a sector is 72° and the sector has an area of 16.2(pie) ft^2. what is the radius of the circle?

Cloud [144]

Sector area = (central angle / 360) * PI * radius^2
sector area = (72 / 360) * PI * radius^2
radius^2 = sector area / [(72 / 360) * PI]
radius^2 = 16.2 * PI / [(1 / 5) * PI]
radius^2 = 16.2 / .2
radius^2 = 81
radius = 9

Source:
http://www.1728.org/radians.htm

6 0

4 years ago

How many different committees can be formed from 6 teachers and 37 students if the committee consists of 4 teachers and 4 stude

Anna [14]

Answer:

The committee of 8 members can be selected in 990,675 different ways.

Step-by-step explanation:

The order in which the teachers and the students are chosen is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

4 teachers from a set of 6.

4 students from a set of 37.

Then

$T = C_{6,4}C_{37,4} = \frac{6!}{4!2!} \times \frac{37!}{4!33!} = 990675$

The committee of 8 members can be selected in 990,675 different ways.

4 0

3 years ago

At a regional soccer tournament, tickets for two adults and seven students cost $60. Tickets for three adults and eleven stude

den301095 [7]

Answer:

The price of an adult ticket is $9 and the price of a student ticket is $6

Step-by-step explanation:

Create a system of equations where x is the price of an adult ticket and y is the price of a student ticket:

2x + 7y = 60

3x + 11y = 93

Solve by elimination by multiplying the top equation by 3 and the bottom equation by -2, to cancel out the x terms:

6x + 21y = 180

-6x - 22y = -186

Add them together:

-y = -6

y = 6

Then, plug in 6 as y into one of the equations to solve for x:

2x + 7y = 60

2x + 7(6) = 60

2x + 42 = 60

2x = 18

x = 9

So, the price of an adult ticket is $9 and the price of a student ticket is $6

8 0

3 years ago

10x + 9y=0<br> 8x + 18y=0

Luba_88 [7]

Answer:

x=0 y=0

Step-by-step explanation:

multiple the first equation by 2

after subtract equation 2 from 1

after getting x you substitute the value of x in any of the equation for your y

3 0

3 years ago

How to solve - 10+5x=7x-4

Triss [41]

10+5x=7x-4
1. simplify 7x - 5x
10=2x-4

2. add four to both sides
10+4=2x
+ 4 4
14=2x

3. divide 14 to both sides
14=2x

x=7

8 0

3 years ago